Problem:
A 2 kg block is moving with a velocity of 4 m/s towards the right. A force of 10 N is applied on the block in the opposite direction. Calculate the acceleration of the block and the time it will take to stop.
Solution:
Given:
Mass of the block (m) = 2 kg
Initial velocity (u) = 4 m/s
Force (F) = 10 N
Using Newton's second law of motion, we can calculate the acceleration:
F = ma
Where,
F = Force applied
m = Mass of the block
a = Acceleration
Rearranging the equation:
a = F/m
Substituting the given values:
a = 10 N / 2 kg
= 5 m/s²
Therefore, the acceleration of the block is 5 m/s².
To calculate the time it will take for the block to stop, we can use the equation:
v = u + at
Where,
v = Final velocity (zero in this case, since the block comes to rest)
u = Initial velocity
a = Acceleration
t = Time
Rearranging the equation:
t = (v - u) / a
Substituting the given values:
t = (0 - 4 m/s) / -5 m/s²
= 4/5 s
= 0.8 s
Therefore, it will take 0.8 seconds for the block to stop.
Sample problem on inertia
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