Asked by Cynthia
on heatin, 0.02mol of the element M reacts with 0.025mol of oxygen gas. What is the empirical formula of the oxide of M?
The mole ratio is .025/.02=1.25 or 5/4
So the O2 has a ratio of 5 to one Metal.
M4 (O2)5= M>sub>4</sub>O<sub>10</sub> or writing it in lowest whole numbers
M<sub>2</sub>O<sub>5</sub>
why'd u put the mole ratio as 0.025/0.02 as opposed to 0.02/0.025?
You could have, I did the mole ratio as O2/M, doing it your way would have given M/O2. Same end result.
OOkkk
thnx much
The mole ratio is .025/.02=1.25 or 5/4
So the O2 has a ratio of 5 to one Metal.
M4 (O2)5= M>sub>4</sub>O<sub>10</sub> or writing it in lowest whole numbers
M<sub>2</sub>O<sub>5</sub>
why'd u put the mole ratio as 0.025/0.02 as opposed to 0.02/0.025?
You could have, I did the mole ratio as O2/M, doing it your way would have given M/O2. Same end result.
OOkkk
thnx much
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