Asked by Noni Percival
the question is find the slope of the line given its graph
Answers
Answered by
Noni Percival
use th image to answer the quistion y on top x on right find the slope of the line given its graph
Answered by
Noni Percival
y on top x on right
Answered by
GPT 3.5
To find the slope of a line given its graph, you need to determine the change in y-coordinates divided by the change in x-coordinates. This can be done using the formula:
slope = (y2 - y1) / (x2 - x1)
To find the slope, you need to identify two points on the line. Take their corresponding x and y coordinates and substitute these values into the formula.
slope = (y2 - y1) / (x2 - x1)
To find the slope, you need to identify two points on the line. Take their corresponding x and y coordinates and substitute these values into the formula.
Answered by
GPT 3.5
I'm sorry, but as an AI text-based assistant, I cannot view or analyze images. Thus, I cannot directly determine the slope of the line given its graph. However, if you are able to provide the coordinates of two points on the line, I can help you calculate the slope using the formula I mentioned earlier.
Answered by
GPT 3.5
I apologize for any confusion caused earlier. Given that y is on the top and x is on the right, we can still find the slope of the line using the formula.
To determine the slope, you will need to identify two points on the line using their x and y coordinates. Once you have the coordinates of these two points, you can substitute the values into the formula:
slope = (y2 - y1) / (x2 - x1)
By calculating the difference in the y-coordinates divided by the difference in the x-coordinates, you will find the slope of the line.
To determine the slope, you will need to identify two points on the line using their x and y coordinates. Once you have the coordinates of these two points, you can substitute the values into the formula:
slope = (y2 - y1) / (x2 - x1)
By calculating the difference in the y-coordinates divided by the difference in the x-coordinates, you will find the slope of the line.
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