Ninêty students auditioned for the school play. One-third of those who auditioned were cast, 6 in major roles. What fraction of those who were cast got major roles? Write your answer as a decimal. (1 point)
5 answers
To find the fraction of those who were cast that got major roles, we need to first find the total number of students who were cast. One-third of the students who auditioned were cast, so $\frac{1}{3}(90)=\boxed{30}$ students were cast. To find the fraction that were cast who got major roles, we divide the number of students with major roles by the total number of students who were cast: $\frac{6}{30}=\boxed{0.2}$.
At Point Pleasant Park, the Advanced Trail is 3.6 times as long as the Medium Trail, and the Medium Trail is 1.2 times as long as the Beginner's Trail. How many times as long as the Beginner's Trail is the Advanced Trail? Write your answer as a decimal. (1 point)
Let's assume that the length of the Beginner's Trail is 1.
The Medium Trail is 1.2 times as long as the Beginner's Trail, so its length is 1 x 1.2 = 1.2.
The Advanced Trail is 3.6 times as long as the Medium Trail, so its length is 1.2 x 3.6 = 4.32.
Therefore, the Advanced Trail is 4.32 times as long as the Beginner's Trail, so the answer as a decimal is $\boxed{4.32}$.
The Medium Trail is 1.2 times as long as the Beginner's Trail, so its length is 1 x 1.2 = 1.2.
The Advanced Trail is 3.6 times as long as the Medium Trail, so its length is 1.2 x 3.6 = 4.32.
Therefore, the Advanced Trail is 4.32 times as long as the Beginner's Trail, so the answer as a decimal is $\boxed{4.32}$.
How much did Mr. Romanov pay for 9.3 gallons of gas at $3.30 a gallon? (1 point)
To find the total cost, we multiply the number of gallons by the price per gallon.
9.3 gallons * $3.30/gallon = $30.69
Therefore, Mr. Romanov paid $\boxed{\$30.69}$ for 9.3 gallons of gas.
9.3 gallons * $3.30/gallon = $30.69
Therefore, Mr. Romanov paid $\boxed{\$30.69}$ for 9.3 gallons of gas.
1 answer