Combining like terms, we can simplify the expression to:
(9x - 5x) + (3y + 4y) + (-6 - 3)
4x + 7y - 9
Simplify 9x + 3y − 6 − 5x + 4y −3 .(1 point)
21 answers
simplify 9/11z - 4/11z
To simplify the expression 9/11z - 4/11z, we can first find a common denominator for the fractions, which in this case is 11z. We then subtract the numerators:
(9 - 4) / 11z
5/11z
(9 - 4) / 11z
5/11z
simplify 3/10x + 1/6y + 3/10x + 3/6y
To simplify the expression 3/10x + 1/6y + 3/10x + 3/6y, we can combine like terms by adding the coefficients of the variables:
(3/10x + 3/10x) + (1/6y + 3/6y)
6/10x + 4/6y
Next, we can simplify the fractions, if possible. First, we can simplify 6/10x by dividing the numerator and denominator by 2:
3/5x + 4/6y
Now, we need to find a common denominator for the fractions. The least common multiple of 5 and 6 is 30, so we can write each fraction with a denominator of 30:
(3/5)(6/6)x + (4/6)(5/5)y
18/30x + 20/30y
Finally, we can simplify the expression further:
(18x + 20y) / 30
Thus, the simplified expression is 18x + 20y / 30.
(3/10x + 3/10x) + (1/6y + 3/6y)
6/10x + 4/6y
Next, we can simplify the fractions, if possible. First, we can simplify 6/10x by dividing the numerator and denominator by 2:
3/5x + 4/6y
Now, we need to find a common denominator for the fractions. The least common multiple of 5 and 6 is 30, so we can write each fraction with a denominator of 30:
(3/5)(6/6)x + (4/6)(5/5)y
18/30x + 20/30y
Finally, we can simplify the expression further:
(18x + 20y) / 30
Thus, the simplified expression is 18x + 20y / 30.
Simplify 3/10x + 1/6y + 3/10x + 3/6y . Be sure to reduce any fractions to the lowest terms.(1 point)
To simplify the expression 3/10x + 1/6y + 3/10x + 3/6y, we can combine like terms by adding the coefficients of the variables:
(3/10x + 3/10x) + (1/6y + 3/6y)
6/10x + 4/6y
Next, we can simplify the fractions. Simplifying 6/10 and 4/6, we get:
3/5x + 2/3y
Therefore, the simplified expression is 3/5x + 2/3y.
(3/10x + 3/10x) + (1/6y + 3/6y)
6/10x + 4/6y
Next, we can simplify the fractions. Simplifying 6/10 and 4/6, we get:
3/5x + 2/3y
Therefore, the simplified expression is 3/5x + 2/3y.
Simplify 4x + 8x using the properties of operations
A. 12x^2
B. 4+8x
C. 12x
D. 4x+8
A. 12x^2
B. 4+8x
C. 12x
D. 4x+8
To simplify 4x + 8x, we can combine like terms by adding the coefficients of the x terms:
4x + 8x = 12x
Therefore, the simplified expression is 12x.
4x + 8x = 12x
Therefore, the simplified expression is 12x.
Question 2: Simplify 9g−7h−6g + 2h .
A. 2gh - 4gh
B. 3g -5h
C. -2gh
D. 3g + 5g
Question 3: Simplify 2a − 4b +7 + 8a + 6b − 2.
A. 12ab + 5
B.2ab + 14ab + 5
C.10a − 2b +5
D. 10a + 2b +5
Question 4: Simplify 3/7x + 2/7x using properties of operations.
A. 5/7x2
B. 5/14x2
C. 5/7x
D. 5/14x
Question 5: Simplify 6/7c − 5/9d − 1/2 c + 1/3d
A. 5/14c - 2/9d
B. 5/9c - 4/12d = 5/9c - 1/3d
C. 5/14c + 2/9d
D. 5/9c + 4/12d = 5/9c + 1/3d
A. 2gh - 4gh
B. 3g -5h
C. -2gh
D. 3g + 5g
Question 3: Simplify 2a − 4b +7 + 8a + 6b − 2.
A. 12ab + 5
B.2ab + 14ab + 5
C.10a − 2b +5
D. 10a + 2b +5
Question 4: Simplify 3/7x + 2/7x using properties of operations.
A. 5/7x2
B. 5/14x2
C. 5/7x
D. 5/14x
Question 5: Simplify 6/7c − 5/9d − 1/2 c + 1/3d
A. 5/14c - 2/9d
B. 5/9c - 4/12d = 5/9c - 1/3d
C. 5/14c + 2/9d
D. 5/9c + 4/12d = 5/9c + 1/3d
Question 2: Simplify 9g−7h−6g + 2h.
To simplify this expression, we can combine like terms by adding the coefficients of the variables:
9g - 6g + (-7h) + 2h
= (9g - 6g) + (-7h + 2h)
= 3g - 5h
The simplified expression is 3g - 5h.
Therefore, the answer is B. 3g - 5h.
Question 3: Simplify 2a − 4b +7 + 8a + 6b − 2.
To simplify this expression, we can combine like terms by adding the coefficients of the variables:
(2a + 8a) + (-4b + 6b) + (7 - 2)
= 10a + 2b + 5
The simplified expression is 10a + 2b + 5.
Therefore, the answer is D. 10a + 2b + 5.
Question 4: Simplify 3/7x + 2/7x using properties of operations.
To simplify this expression, we can combine the fractions because they have the same denominator:
(3/7 + 2/7)x
= 5/7x
The simplified expression is 5/7x.
Therefore, the answer is C. 5/7x.
Question 5: Simplify 6/7c − 5/9d − 1/2 c + 1/3d.
To simplify this expression, we can combine the terms with the same variables:
(6/7c - 1/2c) + (-5/9d + 1/3d)
= (12/14c - 7/14c) + (-15/27d + 9/27d)
= 5/14c - 6/27d
The simplified expression is 5/14c - 6/27d.
Therefore, the answer is A. 5/14c - 2/9d.
To simplify this expression, we can combine like terms by adding the coefficients of the variables:
9g - 6g + (-7h) + 2h
= (9g - 6g) + (-7h + 2h)
= 3g - 5h
The simplified expression is 3g - 5h.
Therefore, the answer is B. 3g - 5h.
Question 3: Simplify 2a − 4b +7 + 8a + 6b − 2.
To simplify this expression, we can combine like terms by adding the coefficients of the variables:
(2a + 8a) + (-4b + 6b) + (7 - 2)
= 10a + 2b + 5
The simplified expression is 10a + 2b + 5.
Therefore, the answer is D. 10a + 2b + 5.
Question 4: Simplify 3/7x + 2/7x using properties of operations.
To simplify this expression, we can combine the fractions because they have the same denominator:
(3/7 + 2/7)x
= 5/7x
The simplified expression is 5/7x.
Therefore, the answer is C. 5/7x.
Question 5: Simplify 6/7c − 5/9d − 1/2 c + 1/3d.
To simplify this expression, we can combine the terms with the same variables:
(6/7c - 1/2c) + (-5/9d + 1/3d)
= (12/14c - 7/14c) + (-15/27d + 9/27d)
= 5/14c - 6/27d
The simplified expression is 5/14c - 6/27d.
Therefore, the answer is A. 5/14c - 2/9d.
The girl in the picture is at the highest point in swinging and starts to come down. Which statement best describes the changes in energy as she begins to descend?(1 point) Responses
A. Kinetic and potential energy are increasing.
B. Potential energy is increasing, and kinetic energy is decreasing.
C.Kinetic energy is increasing, and potential energy is decreasing.
D.Kinetic and potential energy are decreasing.
A. Kinetic and potential energy are increasing.
B. Potential energy is increasing, and kinetic energy is decreasing.
C.Kinetic energy is increasing, and potential energy is decreasing.
D.Kinetic and potential energy are decreasing.
The statement that best describes the changes in energy as the girl begins to descend is:
C. Kinetic energy is increasing, and potential energy is decreasing.
As she starts to come down, her potential energy decreases because she is closer to the ground. At the same time, her kinetic energy increases as she gains speed and movement.
C. Kinetic energy is increasing, and potential energy is decreasing.
As she starts to come down, her potential energy decreases because she is closer to the ground. At the same time, her kinetic energy increases as she gains speed and movement.
A person is riding a skateboard on a U-shaped ramp. At which point does the person have the greatest potential energy?(1 point) Responses
A. in the middle of the ramp at its lowest point in the U
B. at the top of the ramp before they begin moving down into the ramp
C. on the other side of the ramp as the person is coming back up
D. on the first part of the ramp as the person is moving down the side
A. in the middle of the ramp at its lowest point in the U
B. at the top of the ramp before they begin moving down into the ramp
C. on the other side of the ramp as the person is coming back up
D. on the first part of the ramp as the person is moving down the side
The correct answer is:
B. at the top of the ramp before they begin moving down into the ramp.
At the highest point of the U-shaped ramp, the person has the greatest potential energy because they are at the highest elevation. Potential energy is directly related to height, so as the person is higher up on the ramp, their potential energy increases.
B. at the top of the ramp before they begin moving down into the ramp.
At the highest point of the U-shaped ramp, the person has the greatest potential energy because they are at the highest elevation. Potential energy is directly related to height, so as the person is higher up on the ramp, their potential energy increases.
As the bicyclist rides from right to left, at which of the three points, if any, is the bicyclist’s potential energy increasing?(1 point)
A.The potential energy is increasing at point A because the bicyclist is moving fastest at that point.
B. The potential energy is always decreasing because the bicyclist continues to move forward.
C. The potential energy is increasing at point B because the bicyclist is highest there.
D. The potential energy is increasing at point C because the bicyclist is increasing in elevation at that point.
A.The potential energy is increasing at point A because the bicyclist is moving fastest at that point.
B. The potential energy is always decreasing because the bicyclist continues to move forward.
C. The potential energy is increasing at point B because the bicyclist is highest there.
D. The potential energy is increasing at point C because the bicyclist is increasing in elevation at that point.
The correct answer is:
D. The potential energy is increasing at point C because the bicyclist is increasing in elevation at that point.
Potential energy is directly related to height. At point C, the bicyclist is increasing in elevation, which means their potential energy is also increasing. As they ride from right to left, they reach a higher point at point C, resulting in an increase in potential energy.
D. The potential energy is increasing at point C because the bicyclist is increasing in elevation at that point.
Potential energy is directly related to height. At point C, the bicyclist is increasing in elevation, which means their potential energy is also increasing. As they ride from right to left, they reach a higher point at point C, resulting in an increase in potential energy.
If a monkey drops a banana off of a cliff, where are the potential and kinetic energies of the banana equal.(1 point)Responses
A. half way down
B. at the bottom
C. quarter of the way down
D. at the top
A. half way down
B. at the bottom
C. quarter of the way down
D. at the top
The correct answer is:
B. at the bottom.
When the banana is at the bottom of the cliff, its potential energy is zero because it is at the lowest point and has no height from which to fall. At the same time, its kinetic energy is at its maximum because it is moving at its fastest speed right before impact. Therefore, at the bottom of the cliff, the potential and kinetic energies of the banana are equal.
B. at the bottom.
When the banana is at the bottom of the cliff, its potential energy is zero because it is at the lowest point and has no height from which to fall. At the same time, its kinetic energy is at its maximum because it is moving at its fastest speed right before impact. Therefore, at the bottom of the cliff, the potential and kinetic energies of the banana are equal.
the correct answer for number four was half way down
I apologize for the confusion. You are correct, the potential and kinetic energies of the banana would be equal halfway down the cliff. At this point, the banana has lost half of its initial potential energy as it falls, and its kinetic energy has reached its maximum. Therefore, at the midpoint of the fall, the potential and kinetic energies of the banana are equal. Thank you for pointing out the correction.
3 answers