p=ρgh+p₀ = 1025•9.8•10300+101325 =103564825 Pa
F=pA=pπr²=103564825•π•0.13²=5.5•10⁶ N
21. The Mariana trench is located in the Pacific Ocean at a depth of about 10300 m below the surface of the water. The density of seawater is 1025 kg/m3. If an underwater vehicle were to explore such a depth, what force would the water exert on the vehicle's observation window (radius = 0.13 m)?
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Thank you so much!
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