#21 -can you help me solve this equation:
3x^2 (2x - 2)
i keep getting: 6x ^2 -6
#22 can you check this one:
(2x ^2) (6x^2)
i got 12x
#23 can you check this one:
(4m^2 + m -2) + (-m^2 - 3m)
i got: -4m ^2 + 4m-2
#25 can you check this one:
(3x^2 -x -1) + (2x^2 + 2x -1)
i got: -6x ^2 +1x
#26 (-2n^3)(2n)
i am stuck i got: -2n^3 *2n
6 answers
for #26 i got: -4n^4
#22 i got 12 x ^4
#23 should be i got: 5m^2 - 2m -2
# 21
3 x ^ 2 ( 2 x - 2 ) =
3 x ^ 2 * 2 x - 3 x ^ 2 * 2 =
6 x ^ 3 - 6 x ^ 2 =
6 x ^ 2 ( x - 1 )
# 22
( 2 x ^ 2 ) ( 6 x ^ 2 ) =
6 * 2 * x ^ 2 * x ^ 2 =
12 x ^ 4
# 23
( 4 m ^ 2 + m - 2 ) + ( - m ^ 2 - 3 m ) =
4 m ^ 2 + m - 2 - m ^ 2 - 3 m =
3 m ^ 2 - 2 m - 2
# 25
( 3 x ^ 2 - x - 1 ) + ( 2 x ^ 2 + 2 x - 1 ) =
3 x ^ 2 + 2 x ^ 2 - x + 2 x - 1 - 1 =
5 x ^ 2 + x - 2
# 26
( - 2 n ^ 3 )( 2 n ) =
- 2 * 2 * n ^ 3 * n =
- 4 n ^ 4
3 x ^ 2 ( 2 x - 2 ) =
3 x ^ 2 * 2 x - 3 x ^ 2 * 2 =
6 x ^ 3 - 6 x ^ 2 =
6 x ^ 2 ( x - 1 )
# 22
( 2 x ^ 2 ) ( 6 x ^ 2 ) =
6 * 2 * x ^ 2 * x ^ 2 =
12 x ^ 4
# 23
( 4 m ^ 2 + m - 2 ) + ( - m ^ 2 - 3 m ) =
4 m ^ 2 + m - 2 - m ^ 2 - 3 m =
3 m ^ 2 - 2 m - 2
# 25
( 3 x ^ 2 - x - 1 ) + ( 2 x ^ 2 + 2 x - 1 ) =
3 x ^ 2 + 2 x ^ 2 - x + 2 x - 1 - 1 =
5 x ^ 2 + x - 2
# 26
( - 2 n ^ 3 )( 2 n ) =
- 2 * 2 * n ^ 3 * n =
- 4 n ^ 4
bosnian
for #23
i got 5m ^2 - 2m - 2
can you explain this one again
for #23
i got 5m ^2 - 2m - 2
can you explain this one again
( 4 m ^ 2 + m - 2 ) + ( - m ^ 2 - 3 m ) =
4 m ^ 2 + m - 2 + ( - m ^ 2 ) + ( - 3 m ) =
4 m ^ 2 + m - 2 - m ^ 2 - 3 m =
4 m ^ 2 - m ^ 2 + m - 3 m - 2 =
3 m ^ 2 - 2 m - 2
4 m ^ 2 + m - 2 + ( - m ^ 2 ) + ( - 3 m ) =
4 m ^ 2 + m - 2 - m ^ 2 - 3 m =
4 m ^ 2 - m ^ 2 + m - 3 m - 2 =
3 m ^ 2 - 2 m - 2