#21 -can you help me solve this equation:

Question

3x^2 (2x - 2)

i keep getting: 6x ^2 -6

#22 can you check this one:
(2x ^2) (6x^2)
i got 12x

#23 can you check this one:
(4m^2 + m -2) + (-m^2 - 3m)
i got: -4m ^2 + 4m-2

#25 can you check this one:
(3x^2 -x -1) + (2x^2 + 2x -1)

i got: -6x ^2 +1x

#26 (-2n^3)(2n)

i am stuck i got: -2n^3 *2n

Answer 1

for #26 i got: -4n^4

Answer 2

#22 i got 12 x ^4

Answer 3

#23 should be i got: 5m^2 - 2m -2

Answer 4

# 21

3 x ^ 2 ( 2 x - 2 ) =

3 x ^ 2 * 2 x - 3 x ^ 2 * 2 =

6 x ^ 3 - 6 x ^ 2 =

6 x ^ 2 ( x - 1 )

# 22

( 2 x ^ 2 ) ( 6 x ^ 2 ) =

6 * 2 * x ^ 2 * x ^ 2 =

12 x ^ 4

# 23

( 4 m ^ 2 + m - 2 ) + ( - m ^ 2 - 3 m ) =

4 m ^ 2 + m - 2 - m ^ 2 - 3 m =

3 m ^ 2 - 2 m - 2

# 25

( 3 x ^ 2 - x - 1 ) + ( 2 x ^ 2 + 2 x - 1 ) =

3 x ^ 2 + 2 x ^ 2 - x + 2 x - 1 - 1 =

5 x ^ 2 + x - 2

# 26

( - 2 n ^ 3 )( 2 n ) =

- 2 * 2 * n ^ 3 * n =

- 4 n ^ 4

Answer 5

bosnian
for #23
i got 5m ^2 - 2m - 2

can you explain this one again

Answer 6

( 4 m ^ 2 + m - 2 ) + ( - m ^ 2 - 3 m ) =

4 m ^ 2 + m - 2 + ( - m ^ 2 ) + ( - 3 m ) =

4 m ^ 2 + m - 2 - m ^ 2 - 3 m =

4 m ^ 2 - m ^ 2 + m - 3 m - 2 =

3 m ^ 2 - 2 m - 2