HBr + NaOH ==> H2O + NaBr
moles HBr initially = M x L = ??
moles NaOH added = M x L = ??
Whis # mols is larger; that will be the one in excess and (H^+) or (OH^-) (depending upon the one in excess) will equal to the concn of the reagent in excess.
21.00 mL of 0.200 M HBr is titrated with 0.351 M NaOH.
What is the pH after the addition of 6.56 mL of the base ?
2 answers
i still cant make sense of this
4 answers