HBr + NaOH ==> NaBr + HOH
Calculate mols HBr.
mols HBr = M x L = ??
Calculate mols NaOH used = M x L.
Subtract mols of one from mol of the other. The one in excess will give you the H^+ if it is HBr or OH^- if it is NaOH.
Then pH = -log(H^+) OR
pOH = -log(OH^-)
20ml sample of .200M HBr is titrated w/ .200M NaOH. what is the ph after adding 15ml (base)?
1 answer