To find the molecular mass of gas Q, we can use Graham's Law of Effusion.
According to Graham's Law, the rate of effusion of a gas is inversely proportional to the square root of its molar mass.
Rate of effusion of unknown gas Q / Rate of effusion of oxygen gas = √(molar mass of oxygen / molar mass of unknown gas)
Rate of effusion of unknown gas Q = Volume / Time = 20 cm^3 / 12.6 s = 1.587 cm^3/s
Rate of effusion of oxygen gas = 10 cm^3 / 11.2 s = 0.893 cm^3/s
1.587 cm^3/s / 0.893 cm^3/s = √(16 / M)
1.777 = √(16 / M)
1.777^2 = 16 / M
3.159 = 16 / M
M = 16 / 3.159
M ≈ 5.06
Therefore, the molecular mass of unknown gas Q is approximately 5.06.
20cm3 of an unknown gas Q takes 12.6 seconds to pass through small orifice.10cm3 of
oxygen gas takes 11.2 seconds to diffuse through the same orifice under the same
conditions of temperature and pressure .Calculate the molecular mass of unknown gas Q
( O=16)
1 answer
1 answer