In this question, we are given the molecular mass of oxygen as 16. However, we cannot directly use this value because the molecular mass of the unknown gas Q is not given. The molecular mass is a unique property of each individual gas, so we cannot assume that the unknown gas Q has the same molecular mass as oxygen.
To calculate the molecular mass of the unknown gas Q, we can use Graham's law of diffusion, which states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.
Mathematically, we can represent this relationship as:
Rate of diffusion of gas Q / Rate of diffusion of oxygen = √(Molar mass of oxygen / Molar mass of gas Q)
Given that the rate of diffusion of gas Q is 20 cm^3/12.6 s and the rate of diffusion of oxygen is 10 cm^3/11.2 s, we can substitute these values into the equation and solve for the molar mass of gas Q.
(20 cm^3/12.6 s) / (10 cm^3/11.2 s) = √(16 / Molar mass of gas Q)
Solving for the molar mass of gas Q, we get:
Molar mass of gas Q = (16 * 10 * 10) / (20 * 20)
Molar mass of gas Q = 40
Therefore, the molecular mass of the unknown gas Q is 40 g/mol.
20cm3 of an unknown gas Q takes 12.6 seconds to pass through small orifice.10cm3 of
oxygen gas takes 11.2 seconds to diffuse through the same orifice under the same
conditions of temperature and pressure .Calculate the molecular mass of unknown gas Q
( O=16)
in this question why cant you use oxygen 16 ?
1 answer