20cm3 of 0.1m sulphuric acid was required to react with 50.0cm3 of a solution of sodium hydroxide
2 answers
Very interesting but I don't see a question. If you wanted to know the molarity of the NaoH, you need to tell us what indicator was used; i.e.,did 1 or 2 H ions react with the NaOH?. Another point is did you mean 0.1m. That stands for MOLAL, not MOLAR.
2H IONS WAS USED AND ITS MOLAR