In a garden,
5
6
6
5
start fraction, 5, divided by, 6, end fraction of the area is filled with native plants. The native plants take up
107
4
m
2
4
107
m
2
start fraction, 107, divided by, 4, end fraction, start text, m, end text, squared. Let
�
gg represent the total area of the garden.
Select
1
11 multiplication and
1
11 division equation to represent the relationship.
Choose 2 answers:
Choose 2 answers:
(Choice A)
�
×
107
4
=
5
6
g×
4
107
=
6
5
g, times, start fraction, 107, divided by, 4, end fraction, equals, start fraction, 5, divided by, 6, end fraction
A
�
×
107
4
=
5
6
g×
4
107
=
6
5
g, times, start fraction, 107, divided by, 4, end fraction, equals, start fraction, 5, divided by, 6, end fraction
(Choice B)
�
×
5
6
=
107
4
g×
6
5
=
4
107
g, times, start fraction, 5, divided by, 6, end fraction, equals, start fraction, 107, divided by, 4, end fraction
B
�
×
5
6
=
107
4
g×
6
5
=
4
107
g, times, start fraction, 5, divided by, 6, end fraction, equals, start fraction, 107, divided by, 4, end fraction
(Choice C)
107
4
÷
5
6
=
�
4
107
÷
6
5
=gstart fraction, 107, divided by, 4, end fraction, divided by, start fraction, 5, divided by, 6, end fraction, equals, g
C
107
4
÷
5
6
=
�
4
107
÷
6
5
=gstart fraction, 107, divided by, 4, end fraction, divided by, start fraction, 5, divided by, 6, end fraction, equals, g
(Choice D)
5
6
÷
107
4
=
�
6
5
÷
4
107
=gstart fraction, 5, divided by, 6, end fraction, divided by, start fraction, 107, divided by, 4, end fraction, equals, g
D
5
6
÷
107
4
=
�
6
5
÷
4
107
=g
1 answer
D.