4(3z − 7) can be expanded by distributing the 4 to each term inside the parentheses:
4(3z) − 4(7)
Simplifying further:
12z − 28
Expand 4(3z − 7) .
61 answers
show me how to do that
To expand 4(3z - 7), you distribute the 4 to each term inside the parentheses:
First, distribute the 4 to the first term, 3z, in the parentheses:
4 * 3z = 12z
Next, distribute the 4 to the second term, -7, in the parentheses:
4 * -7 = -28
Finally, combine the terms to get the expanded form:
12z - 28
So, the expanded form of 4(3z - 7) is 12z - 28.
First, distribute the 4 to the first term, 3z, in the parentheses:
4 * 3z = 12z
Next, distribute the 4 to the second term, -7, in the parentheses:
4 * -7 = -28
Finally, combine the terms to get the expanded form:
12z - 28
So, the expanded form of 4(3z - 7) is 12z - 28.
Expand −5(2q + 8) .(1 point)
To expand -5(2q + 8), you distribute the -5 to each term inside the parentheses:
First, distribute the -5 to the first term, 2q, in the parentheses:
-5 * 2q = -10q
Next, distribute the -5 to the second term, 8, in the parentheses:
-5 * 8 = -40
Finally, combine the terms to get the expanded form:
-10q - 40
So, the expanded form of -5(2q + 8) is -10q - 40.
First, distribute the -5 to the first term, 2q, in the parentheses:
-5 * 2q = -10q
Next, distribute the -5 to the second term, 8, in the parentheses:
-5 * 8 = -40
Finally, combine the terms to get the expanded form:
-10q - 40
So, the expanded form of -5(2q + 8) is -10q - 40.
Expand 710(5d+6) .
To expand 710(5d + 6), you distribute the 710 to each term inside the parentheses:
First, distribute the 710 to the first term, 5d, in the parentheses:
710 * 5d = 3550d
Next, distribute the 710 to the second term, 6, in the parentheses:
710 * 6 = 4260
Finally, combine the terms to get the expanded form:
3550d + 4260
So, the expanded form of 710(5d + 6) is 3550d + 4260.
First, distribute the 710 to the first term, 5d, in the parentheses:
710 * 5d = 3550d
Next, distribute the 710 to the second term, 6, in the parentheses:
710 * 6 = 4260
Finally, combine the terms to get the expanded form:
3550d + 4260
So, the expanded form of 710(5d + 6) is 3550d + 4260.
Expand 7/10(5d+6) .
To expand 7/10(5d + 6), you distribute the 7/10 to each term inside the parentheses:
First, distribute 7/10 to the first term, 5d, in the parentheses:
(7/10) * 5d = (35/10)d = 3.5d
Next, distribute 7/10 to the second term, 6, in the parentheses:
(7/10) * 6 = (42/10) = 4.2
Finally, combine the terms to get the expanded form:
3.5d + 4.2
So, the expanded form of 7/10(5d + 6) is 3.5d + 4.2.
First, distribute 7/10 to the first term, 5d, in the parentheses:
(7/10) * 5d = (35/10)d = 3.5d
Next, distribute 7/10 to the second term, 6, in the parentheses:
(7/10) * 6 = (42/10) = 4.2
Finally, combine the terms to get the expanded form:
3.5d + 4.2
So, the expanded form of 7/10(5d + 6) is 3.5d + 4.2.
−5/8(3p+8) .
To expand -5/8(3p + 8), you distribute the -5/8 to each term inside the parentheses:
First, distribute -5/8 to the first term, 3p, in the parentheses:
(-5/8) * 3p = -15/8 * p = -15p/8
Next, distribute -5/8 to the second term, 8, in the parentheses:
(-5/8) * 8 = -40/8 = -5
Finally, combine the terms to get the expanded form:
-15p/8 - 5
So, the expanded form of -5/8(3p + 8) is -15p/8 - 5.
First, distribute -5/8 to the first term, 3p, in the parentheses:
(-5/8) * 3p = -15/8 * p = -15p/8
Next, distribute -5/8 to the second term, 8, in the parentheses:
(-5/8) * 8 = -40/8 = -5
Finally, combine the terms to get the expanded form:
-15p/8 - 5
So, the expanded form of -5/8(3p + 8) is -15p/8 - 5.
Use the Order of Operations to simplify (solve) the expression: 24 ÷ 23
- 4 • 5
- 4 • 5
To simplify the expression 24 ÷ 23 - 4 • 5 using the Order of Operations (also known as PEMDAS), we first perform the multiplication/division from left to right and then the addition/subtraction from left to right.
Step 1: Solve the multiplication and division:
24 ÷ 23 = 1.0435 (approximately)
4 • 5 = 20
Step 2: Perform the subtraction:
1.0435 - 20 = -18.9565 (approximately)
So, the simplified expression is approximately -18.9565.
Step 1: Solve the multiplication and division:
24 ÷ 23 = 1.0435 (approximately)
4 • 5 = 20
Step 2: Perform the subtraction:
1.0435 - 20 = -18.9565 (approximately)
So, the simplified expression is approximately -18.9565.
Part A) Jacqueline has two part-time jobs. She earns $15 per hour, b, working as a lab assistant, and $12 per hour, c, working as a cashier. Which algebraic expression below shows how much money Jacqueline earns altogether at her two jobs?(1 point)
The algebraic expression that shows how much money Jacqueline earns altogether at her two jobs is:
15b + 12c
15b + 12c
Part B) If Jacqueline works 2 hours working as a lab assistant and 4 hours as a cashier, how much money will she earn altogether? b = 2 and c = 4(1 point)
To find out how much money Jacqueline will earn altogether if she works 2 hours as a lab assistant (b = 2) and 4 hours as a cashier (c = 4), we substitute the values into the algebraic expression:
15b + 12c
15(2) + 12(4)
30 + 48
78
So, Jacqueline will earn a total of $78 altogether from her two jobs.
15b + 12c
15(2) + 12(4)
30 + 48
78
So, Jacqueline will earn a total of $78 altogether from her two jobs.
Simplify by combining like terms: 5a − 8c + b + 3c −9a + 6b
Type out your answer in the text box.
(1 point)
Type out your answer in the text box.
(1 point)
To simplify by combining like terms:
5a - 8c + b + 3c - 9a + 6b,
we can combine the terms with the same variables:
(5a - 9a) + (- 8c + 3c) + (b + 6b),
which simplifies to:
-4a - 5c + 7b.
Therefore, the simplified expression is:
-4a - 5c + 7b.
5a - 8c + b + 3c - 9a + 6b,
we can combine the terms with the same variables:
(5a - 9a) + (- 8c + 3c) + (b + 6b),
which simplifies to:
-4a - 5c + 7b.
Therefore, the simplified expression is:
-4a - 5c + 7b.
-3(m + 6)
To simplify -3(m + 6), you can distribute the -3 to each term inside the parentheses.
First, distribute -3 to the term m:
-3 * m = -3m
Next, distribute -3 to the term 6:
-3 * 6 = -18
Combine the terms to get the simplified expression:
-3m - 18
So, the simplified form of -3(m + 6) is -3m - 18.
First, distribute -3 to the term m:
-3 * m = -3m
Next, distribute -3 to the term 6:
-3 * 6 = -18
Combine the terms to get the simplified expression:
-3m - 18
So, the simplified form of -3(m + 6) is -3m - 18.
Select the TWO expressions below that are equivalent to 5(x + 3) - 4(2 points)
Responses
5x - 1
5x - 1
5x + 15 - 4
5x + 15 - 4
5x - 5
5x - 5
5x + 11
5x + 11
5x + 3 - 4
Responses
5x - 1
5x - 1
5x + 15 - 4
5x + 15 - 4
5x - 5
5x - 5
5x + 11
5x + 11
5x + 3 - 4
The two equivalent expressions to 5(x + 3) - 4 are:
5x + 15 - 4
and
5x - 5
5x + 15 - 4
and
5x - 5
How can the whole number 378 be expressed as a product of prime numbers with exponents?(1 point)
Responses
14⋅27
14 times 27
2⋅27⋅7
2 times 27 times 7
2⋅33⋅7
2 times 3 cubed times 7
2⋅3⋅3⋅3⋅7
Responses
14⋅27
14 times 27
2⋅27⋅7
2 times 27 times 7
2⋅33⋅7
2 times 3 cubed times 7
2⋅3⋅3⋅3⋅7
To express the whole number 378 as a product of prime numbers with exponents, you need to factorize it.
The correct expression is:
2 * 3 * 3 * 3 * 7
This means that 378 can be expressed as the product of the prime numbers 2, 3, and 7, with the exponents 1, 3, and 1, respectively.
The correct expression is:
2 * 3 * 3 * 3 * 7
This means that 378 can be expressed as the product of the prime numbers 2, 3, and 7, with the exponents 1, 3, and 1, respectively.
Find the GCF of 18j+27 .(1 point)
Responses
18
18
54
54
9
9
3
Responses
18
18
54
54
9
9
3
To find the greatest common factor (GCF) of 18j + 27, we can first factor out any common factors between the terms.
The GCF between 18 and 27 is 9, so we can factor out 9:
18j + 27 = 9(2j + 3)
Therefore, the GCF of 18j + 27 is 9.
The GCF between 18 and 27 is 9, so we can factor out 9:
18j + 27 = 9(2j + 3)
Therefore, the GCF of 18j + 27 is 9.
Find the GCF of 42m−28n .(1 point)
Responses
84
84
7
7
2
2
14
Responses
84
84
7
7
2
2
14
To find the greatest common factor (GCF) of 42m - 28n, we can first factor out any common factors between the terms.
The GCF between 42 and 28 is 14, and there are no common variables.
Therefore, the GCF of 42m - 28n is 14.
The GCF between 42 and 28 is 14, and there are no common variables.
Therefore, the GCF of 42m - 28n is 14.
Use properties of operations to factor 8w + 16 using the GCF. (1 point)
Responses
2(4w + 8)
2 Left Parenthesis 4 w plus 8 Right Parenthesis
4(2w + 4)
4 Left Parenthesis 2 w plus 4 Right Parenthesis
6(2w + 10)
6 Left Parenthesis 2 w plus 10 Right Parenthesis
8(w + 2)
Responses
2(4w + 8)
2 Left Parenthesis 4 w plus 8 Right Parenthesis
4(2w + 4)
4 Left Parenthesis 2 w plus 4 Right Parenthesis
6(2w + 10)
6 Left Parenthesis 2 w plus 10 Right Parenthesis
8(w + 2)
To factor 8w + 16 using the greatest common factor (GCF), we first determine the GCF of 8 and 16, which is 8.
Next, we divide each term by the GCF, 8:
8w ÷ 8 = w
16 ÷ 8 = 2
Finally, we rewrite the expression using the GCF and the divided terms:
8w + 16 = 8(w + 2)
So, using the GCF, 8w + 16 can be factored as 8(w + 2).
Next, we divide each term by the GCF, 8:
8w ÷ 8 = w
16 ÷ 8 = 2
Finally, we rewrite the expression using the GCF and the divided terms:
8w + 16 = 8(w + 2)
So, using the GCF, 8w + 16 can be factored as 8(w + 2).
Factor −27h + 6 using the GCF. (1 point)
Responses
3(9h + 2)
3 Left Parenthesis 9 h plus 2 Right Parenthesis
3(−9h + 2)
3 Left Parenthesis negative 9 h plus 2 Right Parenthesis
3(−9h − 2)
3 Left Parenthesis negative 9 h minus 2 Right Parenthesis
3(9h − 2)
Responses
3(9h + 2)
3 Left Parenthesis 9 h plus 2 Right Parenthesis
3(−9h + 2)
3 Left Parenthesis negative 9 h plus 2 Right Parenthesis
3(−9h − 2)
3 Left Parenthesis negative 9 h minus 2 Right Parenthesis
3(9h − 2)
To factor -27h + 6 using the greatest common factor (GCF), we first determine the GCF of -27 and 6, which is 3.
Next, we divide each term by the GCF, 3:
-27h ÷ 3 = -9h
6 ÷ 3 = 2
Finally, we rewrite the expression using the GCF and the divided terms:
-27h + 6 = 3(-9h + 2)
So, using the GCF, -27h + 6 can be factored as 3(-9h + 2).
Next, we divide each term by the GCF, 3:
-27h ÷ 3 = -9h
6 ÷ 3 = 2
Finally, we rewrite the expression using the GCF and the divided terms:
-27h + 6 = 3(-9h + 2)
So, using the GCF, -27h + 6 can be factored as 3(-9h + 2).
How can the whole number 125 be expressed as a product of prime numbers with exponents?(1 point)
To express the whole number 125 as a product of prime numbers with exponents, you need to factorize it.
The correct expression is:
5^3
This means that 125 can be expressed as 5 raised to the power of 3.
The correct expression is:
5^3
This means that 125 can be expressed as 5 raised to the power of 3.
Find the GCF of 15q+6 .
To find the greatest common factor (GCF) of 15q + 6, we can first look for any common factors between the terms.
The GCF between 15 and 6 is 3, and there are no common variables in this case.
Therefore, the GCF of 15q + 6 is 3.
The GCF between 15 and 6 is 3, and there are no common variables in this case.
Therefore, the GCF of 15q + 6 is 3.
Find the GCF of 8d−20 .
To find the greatest common factor (GCF) of 8d - 20, we can first look for any common factors between the terms.
Both 8d and 20 are divisible by 4, so we can factor out 4:
8d - 20 = 4(2d - 5)
Therefore, the GCF of 8d - 20 is 4.
Both 8d and 20 are divisible by 4, so we can factor out 4:
8d - 20 = 4(2d - 5)
Therefore, the GCF of 8d - 20 is 4.
Factor 9z + 18 using the GCF.
To factor 9z + 18 using the greatest common factor (GCF), we first determine the GCF of 9 and 18, which is 9.
Next, we divide each term by the GCF, 9:
9z ÷ 9 = z
18 ÷ 9 = 2
Finally, we rewrite the expression using the GCF and the divided terms:
9z + 18 = 9(z + 2)
So, using the GCF, 9z + 18 can be factored as 9(z + 2).
Next, we divide each term by the GCF, 9:
9z ÷ 9 = z
18 ÷ 9 = 2
Finally, we rewrite the expression using the GCF and the divided terms:
9z + 18 = 9(z + 2)
So, using the GCF, 9z + 18 can be factored as 9(z + 2).
Factor 16d − 12 using the GCF
To factor 16d - 12 using the greatest common factor (GCF), we first determine the GCF of 16 and 12, which is 4.
Next, we divide each term by the GCF, 4:
16d ÷ 4 = 4d
12 ÷ 4 = 3
Finally, we rewrite the expression using the GCF and the divided terms:
16d - 12 = 4(4d - 3)
So, using the GCF, 16d - 12 can be factored as 4(4d - 3).
Next, we divide each term by the GCF, 4:
16d ÷ 4 = 4d
12 ÷ 4 = 3
Finally, we rewrite the expression using the GCF and the divided terms:
16d - 12 = 4(4d - 3)
So, using the GCF, 16d - 12 can be factored as 4(4d - 3).
Add: 12(x+4)+14(4x−2) . Answer should be in mixed number form.
To add 12(x + 4) + 14(4x - 2), we can simplify each term before combining them.
First, distribute 12 and 14 to each term within the parentheses:
12(x + 4) = 12x + 48
14(4x - 2) = 56x - 28
Now, combine like terms:
12x + 48 + 56x - 28
Adding the x terms and the constant terms separately:
12x + 56x + 48 - 28
68x + 20
Therefore, the sum of 12(x + 4) + 14(4x - 2) is 68x + 20.
First, distribute 12 and 14 to each term within the parentheses:
12(x + 4) = 12x + 48
14(4x - 2) = 56x - 28
Now, combine like terms:
12x + 48 + 56x - 28
Adding the x terms and the constant terms separately:
12x + 56x + 48 - 28
68x + 20
Therefore, the sum of 12(x + 4) + 14(4x - 2) is 68x + 20.
Add: 1/2(x+4)+14(4x−2) . Answer should be in mixed number form.(1 point
To add 1/2(x + 4) + 14(4x - 2), we can simplify each term before combining them.
First, distribute 1/2 and 14 to each term within the parentheses:
1/2(x + 4) = 1/2x + 2
14(4x - 2) = 56x - 28
Now, combine like terms:
1/2x + 2 + 56x - 28
Adding the x terms and the constant terms separately:
1/2x + 56x + 2 - 28
56 1/2x - 26
Therefore, the sum of 1/2(x + 4) + 14(4x - 2) is 56 1/2x - 26.
First, distribute 1/2 and 14 to each term within the parentheses:
1/2(x + 4) = 1/2x + 2
14(4x - 2) = 56x - 28
Now, combine like terms:
1/2x + 2 + 56x - 28
Adding the x terms and the constant terms separately:
1/2x + 56x + 2 - 28
56 1/2x - 26
Therefore, the sum of 1/2(x + 4) + 14(4x - 2) is 56 1/2x - 26.
Add: (4d−3)+(12d+4)
To add (4d - 3) + (12d + 4), we can combine like terms:
4d - 3 + 12d + 4
Combining the d terms and the constant terms separately:
(4d + 12d) + (-3 + 4)
16d + 1
Therefore, the sum of (4d - 3) + (12d + 4) is 16d + 1.
4d - 3 + 12d + 4
Combining the d terms and the constant terms separately:
(4d + 12d) + (-3 + 4)
16d + 1
Therefore, the sum of (4d - 3) + (12d + 4) is 16d + 1.
Add: (2m−3)+(3n−1)+(3m+1)
To add (2m - 3) + (3n - 1) + (3m + 1), we can group like terms together and then combine them:
(2m + 3m) + (-3 + 1 + 1) + (3n)
This simplifies to:
5m - 1 + 3n
Therefore, the sum of (2m - 3) + (3n - 1) + (3m + 1) is 5m - 1 + 3n.
(2m + 3m) + (-3 + 1 + 1) + (3n)
This simplifies to:
5m - 1 + 3n
Therefore, the sum of (2m - 3) + (3n - 1) + (3m + 1) is 5m - 1 + 3n.
Subtract: 2(10b+4)−(b−2) .
To subtract 2(10b + 4) - (b - 2), we can simplify the expression by distributing the 2 to the terms within the parentheses:
2(10b + 4) - (b - 2)
= 20b + 8 - (b - 2)
= 20b + 8 - b + 2
Next, combine like terms:
= (20b - b) + (8 + 2)
= 19b + 10
Therefore, the subtraction of 2(10b + 4) - (b - 2) is 19b + 10.
2(10b + 4) - (b - 2)
= 20b + 8 - (b - 2)
= 20b + 8 - b + 2
Next, combine like terms:
= (20b - b) + (8 + 2)
= 19b + 10
Therefore, the subtraction of 2(10b + 4) - (b - 2) is 19b + 10.
Subtract: (3g−4)−2(3g+4) .
To subtract (3g - 4) - 2(3g + 4), we can first distribute the -2 to the terms within the second parentheses:
(3g - 4) - 2(3g + 4)
= 3g - 4 - 2(3g) - 2(4)
= 3g - 4 - 6g - 8
Next, combine like terms:
= (3g - 6g) + (-4 - 8)
= -3g - 12
Therefore, the subtraction of (3g - 4) - 2(3g + 4) is -3g - 12.
(3g - 4) - 2(3g + 4)
= 3g - 4 - 2(3g) - 2(4)
= 3g - 4 - 6g - 8
Next, combine like terms:
= (3g - 6g) + (-4 - 8)
= -3g - 12
Therefore, the subtraction of (3g - 4) - 2(3g + 4) is -3g - 12.
Use the properties of operations to add 9(k+13)+10(12k−1) .(1 point)
Responses
1912k−23
19 Start Fraction 1 over 2 End Fraction k minus Start Fraction 2 over 3 End Fraction
14k−7
14 k minus 7
14k−23
14 k minus Start Fraction 2 over 3 End Fraction
14k+13
Responses
1912k−23
19 Start Fraction 1 over 2 End Fraction k minus Start Fraction 2 over 3 End Fraction
14k−7
14 k minus 7
14k−23
14 k minus Start Fraction 2 over 3 End Fraction
14k+13
Use the properties of operations to add 4(g−2)+(g+2) .(1 point)
Responses
5g+10
5 g plus 10
5g−6
5 g minus 6
5g−10
5 g minus 10
5g
Responses
5g+10
5 g plus 10
5g−6
5 g minus 6
5g−10
5 g minus 10
5g
Use the properties of operations to subtract (h+k)−(2k−h) .(1 point)
Responses
2h−k
2 h minus k
2h+k
2 h plus k
−2h−k
negative 2 h minus k
−k
Responses
2h−k
2 h minus k
2h+k
2 h plus k
−2h−k
negative 2 h minus k
−k
Use the properties of operations to subtract (p−3)−(2.4+2p) .(1 point)
Responses
p−5.4
p minus 5.4
−p−5.4
negative p minus 5.4
3p−5.4
3 p minus 5.4
−p+5.4
Responses
p−5.4
p minus 5.4
−p−5.4
negative p minus 5.4
3p−5.4
3 p minus 5.4
−p+5.4
Subtract: 2(k−4)−3(2k−1) .(1 point)
Responses
−4k−5
negative 4 k minus 5
−6k−18
negative 6 k minus 18
8k−11
8 k minus 11
−4k−11
Responses
−4k−5
negative 4 k minus 5
−6k−18
negative 6 k minus 18
8k−11
8 k minus 11
−4k−11
bot im done with you