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Use the properties of operations to add 9(k+1/3)+10(1/2k−1).Asked by No One
Use the properties of operations to add 9(k+1/3)+10(1/2k−1) .
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To add the expression 9(k + 1/3) + 10(1/2k - 1), we can use the distributive property and combine like terms.
First, distribute 9 to both terms inside the parentheses:
9 * k + 9 * (1/3) + 10(1/2k - 1)
This simplifies to:
9k + 3/3 + 10(1/2k) + 10(-1)
Since 3/3 is equal to 1, we can write:
9k + 1 + 10(1/2k) - 10
Now distribute 10 to both terms inside the parentheses:
9k + 1 + 10/2k - 10
Simplifying further, we have:
9k + 1 + 5k - 10
Combine like terms:
14k - 9
Therefore, 9(k + 1/3) + 10(1/2k - 1) simplifies to 14k - 9.
First, distribute 9 to both terms inside the parentheses:
9 * k + 9 * (1/3) + 10(1/2k - 1)
This simplifies to:
9k + 3/3 + 10(1/2k) + 10(-1)
Since 3/3 is equal to 1, we can write:
9k + 1 + 10(1/2k) - 10
Now distribute 10 to both terms inside the parentheses:
9k + 1 + 10/2k - 10
Simplifying further, we have:
9k + 1 + 5k - 10
Combine like terms:
14k - 9
Therefore, 9(k + 1/3) + 10(1/2k - 1) simplifies to 14k - 9.
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