Use the properties of operations to add 9(k+1/3) +10 (1/2k−1) . (1 point)

Answer 1

To add 9(k+1/3) +10 (1/2k−1), we can distribute the numbers outside of the parentheses. When we do this, we get:

9k + (9)(1/3) + 10(1/2k) - 10(1)

Simplifying each term:

9k + 3 + 5/k - 10

Combining like terms:

9k + 5/k - 7

Therefore, the sum of 9(k+1/3) +10 (1/2k−1) is 9k + 5/k - 7.

Answer 2

Use the properties of operations to add 4(g−2)+(g+2) .(1 point)

Answer 3

To add 4(g-2) + (g+2), we can use the distributive property to multiply each term inside the parentheses:

4g - 8 + g + 2

Combining like terms:

4g + g - 8 + 2

5g - 6

Therefore, the sum of 4(g-2) + (g+2) is 5g - 6.

Answer 4

Use the properties of operations to subtract (h+k)−(2k−h) .(1 point)

Answer 5

To subtract (h+k) - (2k-h), we can distribute the negative sign to each term inside the parentheses:

h + k - 2k + h

Rearranging the terms:

(h + h) + (k - 2k)

Combining like terms:

2h - k

Therefore, the difference of (h+k) - (2k-h) is 2h - k.

Answer 6

Use the properties of operations to subtract (p−3)−(2.4+2p) .(1 point)

Answer 7

To subtract (p-3) - (2.4+2p), we can distribute the negative sign to each term inside the second set of parentheses:

p - 3 - 2.4 - 2p

Rearranging the terms:

(p - 2p) - (3 + 2.4)

Combining like terms:

-p - 5.4

Therefore, the difference of (p-3) - (2.4+2p) is -p - 5.4.

Answer 8

Subtract: 2(k−4)−3(2k−1) .(1 point)

Answer 9

To subtract 2(k-4) - 3(2k-1), we can distribute the numbers outside of the parentheses:

2k - 8 - 6k + 3

Combine like terms:

-4k - 5

Therefore, the difference of 2(k-4) - 3(2k-1) is -4k - 5.