According to the Law of Conservation of Mass, the mass of the products should be equal to the mass of the reactants.
The molar mass of potassium (K) is 39.10 g/mol, and the molar mass of chlorine (Cl) is 35.45 g/mol.
So, the moles of potassium (K) in 78 g would be 78 g / 39.10 g/mol = 2 moles.
The moles of chlorine (Cl) in 71 g would be 71 g / 35.45 g/mol = 2 moles.
The balanced equation for the reaction is: 2K + Cl2 → 2KCl
Since 2 moles of potassium react to form 2 moles of potassium chloride (KCl), the mass of 2KCl would be equal to the sum of the masses of 2 moles of potassium chloride, which is 2 * (39.10 g/mol + 35.45 g/mol) = 148.10 g.
Therefore, the mass of the product 2KCl is 148.10 g.
78 g of potassium (K) react with 71 g of chlorine (Cl) to produce potassium chloride. According to the Law of Conservation of Mass, what is the mass of the product (2KCl)? (1 point) Responses 149 g 149 g 156 g 156 g 4 g 4 g 2 g
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