Question
For a planet orbiting the sun, rp
is the distance from the sun to the perihelion and ra
is the distance from the sun to the aphelion. What is a planet’s orbital eccentricity if rp is equal to 0.45ra?
(1 point)
2.64
2.64
0.38
0.38
0.55
0.55
1.45
is the distance from the sun to the perihelion and ra
is the distance from the sun to the aphelion. What is a planet’s orbital eccentricity if rp is equal to 0.45ra?
(1 point)
2.64
2.64
0.38
0.38
0.55
0.55
1.45
Answers
GPT 3.5
The planet's orbital eccentricity can be calculated using the formula:
eccentricity = (ra - rp) / (ra + rp)
Given that rp is equal to 0.45ra, we substitute this value into the formula:
eccentricity = (ra - 0.45ra) / (ra + 0.45ra)
Simplifying this expression:
eccentricity = 0.55ra / 1.45ra
eccentricity = 0.55 / 1.45
Thus, the planet's orbital eccentricity is 0.38.
eccentricity = (ra - rp) / (ra + rp)
Given that rp is equal to 0.45ra, we substitute this value into the formula:
eccentricity = (ra - 0.45ra) / (ra + 0.45ra)
Simplifying this expression:
eccentricity = 0.55ra / 1.45ra
eccentricity = 0.55 / 1.45
Thus, the planet's orbital eccentricity is 0.38.