what is the acceleration of a ball rolling 12 m/s to a STOP in 3 seconds

Answer 1

To calculate the acceleration of a ball rolling from 12 m/s to a stop in 3 seconds, we need to use the equation:

acceleration = (final velocity - initial velocity) / time

Where:
Initial velocity (u) = 12 m/s
Final velocity (v) = 0 m/s (since the ball comes to a stop)
Time (t) = 3 seconds

Using the given values in the equation:

acceleration = (0 m/s - 12 m/s) / 3 s
acceleration = -12 m/s / 3 s
acceleration = -4 m/s²

Therefore, the acceleration of the ball rolling from 12 m/s to a stop in 3 seconds is -4 m/s². Here, the negative sign indicates that the ball is decelerating or slowing down.