Asked by Matt
I do not understand these problems. :S
I'd really appreciate the help.
Use trigonometric identities to transform the left side of the equation into the right side.
cot O sin O = cos O
sin^2 O - cos^2O = 2sin^2 O -1
(tan O + cot O)/tan O = csc^2 O
I'd really appreciate the help.
Use trigonometric identities to transform the left side of the equation into the right side.
cot O sin O = cos O
sin^2 O - cos^2O = 2sin^2 O -1
(tan O + cot O)/tan O = csc^2 O
Answers
Answered by
Reiny
for most of these you have to know your basic trig relationships
tanx = sinx/cosx ; cotx = cosx/sinx
cscx = 1/sinx ; secx = 1/cosx
sin<sup>2</sup>x + cos<sup>2</sup>x = 1
and its re-arrangements.
so for the first :
LS = cotOsinO
= (cosO/sinO)(sinO)
= sinO
= RS
Most are this easy.
last one : (I will use x as my angle)
LS
= (sinx/cosx + cosx/ sinx)/(sinx/cosx)
= (sin<sup>2</sup>x + cos<sup>2</sup>x)/(sinxcosx) x (cosx/sinx)
= 1/(sinxcosx)(cosx/sinx)
= 1/sin<sup>2</sup>x
= csc<sup>2</sup>x
= RS
try the second one, it is even easier.
tanx = sinx/cosx ; cotx = cosx/sinx
cscx = 1/sinx ; secx = 1/cosx
sin<sup>2</sup>x + cos<sup>2</sup>x = 1
and its re-arrangements.
so for the first :
LS = cotOsinO
= (cosO/sinO)(sinO)
= sinO
= RS
Most are this easy.
last one : (I will use x as my angle)
LS
= (sinx/cosx + cosx/ sinx)/(sinx/cosx)
= (sin<sup>2</sup>x + cos<sup>2</sup>x)/(sinxcosx) x (cosx/sinx)
= 1/(sinxcosx)(cosx/sinx)
= 1/sin<sup>2</sup>x
= csc<sup>2</sup>x
= RS
try the second one, it is even easier.
Answered by
Steve Madden
solve for x to the nearest thousandth: 2tan square x-5tan x-1
Answered by
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12
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