In liposuction, a doctor removes fat deposits from a person's body. If body fat has a density of 0.909 g/mL and 1.5 L of fat is removed, how many pounds of are removed from the patient? Express your answer using two significant figures

Answer 1

To find the pounds of fat removed from the patient, we need to convert the volume of fat removed (1.5 L) to its mass and then to pounds.

First, we need to convert L to mL since the density of fat is given in g/mL:
1 L = 1000 mL

So, 1.5 L = 1500 mL

To find the mass of the fat, we multiply the volume by the density:
Mass = Volume x Density
Mass = 1500 mL x 0.909 g/mL

Mass = 1363.5 g

Next, we need to convert grams to pounds.

Since 1 pound is approximately equal to 453.592 grams, we can set up a conversion factor:
1 lb / 453.592 g

So, the number of pounds of fat removed is:
1363.5 g * (1 lb / 453.592 g) ≈ 3.00 lb.

Rounded to two significant figures, the number of pounds of fat removed from the patient is 3.00 lb.