Question

An NFL kicker misses 2 out of every 11 field goals. If he missed 8 field goals throughout the season, how many did he attempt?

Answer 1

Let's assume the number of field goals attempted throughout the season is x.
The number of missed field goals is 2/11 * x = 8.
Thus, 2/11 * x = 8.
Dividing both sides by 2/11 gives x = 8 / (2/11) = 8 * (11/2) = <<8/(2/11)*11=44>>44.
Therefore, he attempted 44 field goals throughout the season. Answer: \boxed{44}.

Answer 2

An NFL kicker misses 2 out of every 11 field goals. If he missed 8 field goals throughout the season, how many did he attempt?
(Step by step)

Answer 3

Let's assume the number of field goals attempted throughout the season is x.

According to the given scenario, the kicker misses 2 out of every 11 field goals. So, the number of successful field goals is 11 - 2 = 9 out of every 11.

We can set up a proportion to solve for x:
9/11 = (x - 8)/x

Next, let's cross-multiply and simplify the equation:
9x = 11(x - 8)
9x = 11x - 88
88 = 11x - 9x
88 = 2x
44 = x

Therefore, the kicker attempted 44 field goals throughout the season. Answer: 44.

Answer 4

An NFL kicker misses 2 out of every 11 field goals. If he missed 8 field goals throughout the season, how many did he attempt?
(Only show the proportion)

Answer 5

Let x be the total number of field goals attempted throughout the season.

The proportion can be set up as:

(2/11) = 8/x