The area of a triangle is calculated using the formula: Area = (base * height) / 2.
Plugging in the given values, we have:
Area = (20 * 12) / 2
Area = 240 / 2
Area = 120 square inches
Therefore, the correct answer is 120 square inches.
What is the area of a triangle with a base of 20 inches and a height of 12 inches?(1 point)
Responses
120 square inches
104.5 square inches
240 square inches
180 square inches
19 answers
What is the area of a circle with a radius of 7 inches. round to the nearest tenth. (1 point)
Responses
153.9 square inches
44.0 square inches
128.7 square inches
76.2 square inches
Responses
153.9 square inches
44.0 square inches
128.7 square inches
76.2 square inches
The area of a circle is calculated using the formula: Area = π * r^2, where π is a constant value approximately equal to 3.14159 and r is the radius of the circle.
Plugging in the given value, we have:
Area = 3.14159 * (7)^2
Area = 3.14159 * 49
Area ≈ 153.938 square inches
Rounding to the nearest tenth, the area of the circle is approximately 153.9 square inches.
Therefore, the correct answer is 153.9 square inches.
Plugging in the given value, we have:
Area = 3.14159 * (7)^2
Area = 3.14159 * 49
Area ≈ 153.938 square inches
Rounding to the nearest tenth, the area of the circle is approximately 153.9 square inches.
Therefore, the correct answer is 153.9 square inches.
Please select if the following naming rules apply to a line or a line segment.(5 points)
– Use the 2 endpoints
– Use a bar with two arrows over the top
– Use 1 lower case script letter
– Use any two points
– Use a bar over the top
– Use the 2 endpoints
– Use a bar with two arrows over the top
– Use 1 lower case script letter
– Use any two points
– Use a bar over the top
- Use the 2 endpoints: Line segment
- Use a bar with two arrows over the top: Line
- Use 1 lower case script letter: Both a line and a line segment
- Use any two points: Both a line and a line segment
- Use a bar over the top: Line
- Use a bar with two arrows over the top: Line
- Use 1 lower case script letter: Both a line and a line segment
- Use any two points: Both a line and a line segment
- Use a bar over the top: Line
you can't pick both a line and a line segment for these responses
I apologize for the mistake. Let me correct my response:
- Use the 2 endpoints: Line segment
- Use a bar with two arrows over the top: Line
- Use 1 lower case script letter: Line segment
- Use any two points: Line segment
- Use a bar over the top: Line
- Use the 2 endpoints: Line segment
- Use a bar with two arrows over the top: Line
- Use 1 lower case script letter: Line segment
- Use any two points: Line segment
- Use a bar over the top: Line
thank you
You're welcome! If you have any more questions, feel free to ask.
The midpoint of UV¯¯¯¯¯¯¯¯
is (4,3). The coordinates of one endpoint are U (11, -2). Find the coordinates of the other endpoint, V. (1 point)
Responses
(-6,4)
(7.5, -.5)
(-7,-2)
(-3,8)
is (4,3). The coordinates of one endpoint are U (11, -2). Find the coordinates of the other endpoint, V. (1 point)
Responses
(-6,4)
(7.5, -.5)
(-7,-2)
(-3,8)
To find the coordinates of the other endpoint V, we can use the midpoint formula.
The midpoint formula states that the coordinates of the midpoint (M) between two endpoints (A and B) can be found using the following formulas:
x-coordinate of midpoint = (x-coordinate of A + x-coordinate of B) / 2
y-coordinate of midpoint = (y-coordinate of A + y-coordinate of B) / 2
In this case, the coordinates of the midpoint are (4,3), and the coordinates of endpoint U are (11,-2).
Using the midpoint formula, we can solve for the coordinates of endpoint V as follows:
x-coordinate of V = 2 * x-coordinate of midpoint - x-coordinate of U
= 2 * 4 - 11
= 8 - 11
= -3
y-coordinate of V = 2 * y-coordinate of midpoint - y-coordinate of U
= 2 * 3 - (-2)
= 6 + 2
= 8
Therefore, the coordinates of the other endpoint V are (-3,8).
The correct answer is (-3,8).
The midpoint formula states that the coordinates of the midpoint (M) between two endpoints (A and B) can be found using the following formulas:
x-coordinate of midpoint = (x-coordinate of A + x-coordinate of B) / 2
y-coordinate of midpoint = (y-coordinate of A + y-coordinate of B) / 2
In this case, the coordinates of the midpoint are (4,3), and the coordinates of endpoint U are (11,-2).
Using the midpoint formula, we can solve for the coordinates of endpoint V as follows:
x-coordinate of V = 2 * x-coordinate of midpoint - x-coordinate of U
= 2 * 4 - 11
= 8 - 11
= -3
y-coordinate of V = 2 * y-coordinate of midpoint - y-coordinate of U
= 2 * 3 - (-2)
= 6 + 2
= 8
Therefore, the coordinates of the other endpoint V are (-3,8).
The correct answer is (-3,8).
Given the points below, find the distance from X to Y. Round to the nearest hundredth.
X(-9,2) and Y(5, -4)
(1 point)
Responses
15.2
4.5
7.2
13.8
X(-9,2) and Y(5, -4)
(1 point)
Responses
15.2
4.5
7.2
13.8
To find the distance between two points (X and Y) in a coordinate plane, we can use the distance formula:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the coordinates of point X are (-9,2) and the coordinates of point Y are (5,-4).
Using the distance formula, we can substitute the values and calculate the distance:
Distance = √((5 - (-9))^2 + (-4 - 2)^2)
= √((5 + 9)^2 + (-4 - 2)^2)
= √(14^2 + (-6)^2)
= √(196 + 36)
= √232
≈ 15.23
Rounding to the nearest hundredth, the distance from X to Y is approximately 15.23.
Therefore, the correct answer is 15.2.
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the coordinates of point X are (-9,2) and the coordinates of point Y are (5,-4).
Using the distance formula, we can substitute the values and calculate the distance:
Distance = √((5 - (-9))^2 + (-4 - 2)^2)
= √((5 + 9)^2 + (-4 - 2)^2)
= √(14^2 + (-6)^2)
= √(196 + 36)
= √232
≈ 15.23
Rounding to the nearest hundredth, the distance from X to Y is approximately 15.23.
Therefore, the correct answer is 15.2.
If line n bisects CE¯¯¯¯¯¯¯¯
, Find CD.
CD = x+6
CE = 4x-21
, Find CD.
CD = x+6
CE = 4x-21
If line n bisects CE¯¯¯¯¯, it means that CD¯¯¯¯¯ and DE¯¯¯¯¯ are equal in length.
Since CE = CD + DE, and CD¯¯¯¯¯ and DE¯¯¯¯¯ are equal in length, we can set up an equation:
CE = 2 * CD
Substituting the given values, we have:
4x - 21 = 2 * (x + 6)
Simplifying the equation:
4x - 21 = 2x + 12
Subtracting 2x from both sides:
2x - 21 = 12
Adding 21 to both sides:
2x = 33
Dividing both sides by 2:
x = 16.5
So, CD = x + 6 = 16.5 + 6 = 22.5
Therefore, CD is equal to 22.5.
Since CE = CD + DE, and CD¯¯¯¯¯ and DE¯¯¯¯¯ are equal in length, we can set up an equation:
CE = 2 * CD
Substituting the given values, we have:
4x - 21 = 2 * (x + 6)
Simplifying the equation:
4x - 21 = 2x + 12
Subtracting 2x from both sides:
2x - 21 = 12
Adding 21 to both sides:
2x = 33
Dividing both sides by 2:
x = 16.5
So, CD = x + 6 = 16.5 + 6 = 22.5
Therefore, CD is equal to 22.5.
<1 and <2 are supplementary angles. m<1 is 2y+12 and the m<2 is 8y+8. Find m<2. You must show all steps and work in order to receive full credit. (2 points)
If two angles are supplementary, their measures add up to 180 degrees.
In this case, we have the following equations:
m∠1 = 2y + 12
m∠2 = 8y + 8
We know that the sum of m∠1 and m∠2 is 180 degrees:
m∠1 + m∠2 = 180
Substituting the given equations into the sum equation, we have:
(2y + 12) + (8y + 8) = 180
Combining like terms:
10y + 20 = 180
Subtracting 20 from both sides:
10y = 160
Dividing both sides by 10:
y = 16
Now that we know the value of y, we can substitute it back into the equation for m∠2:
m∠2 = 8y + 8 = 8(16) + 8 = 128 + 8 = 136
Therefore, m∠2 is equal to 136 degrees.
In this case, we have the following equations:
m∠1 = 2y + 12
m∠2 = 8y + 8
We know that the sum of m∠1 and m∠2 is 180 degrees:
m∠1 + m∠2 = 180
Substituting the given equations into the sum equation, we have:
(2y + 12) + (8y + 8) = 180
Combining like terms:
10y + 20 = 180
Subtracting 20 from both sides:
10y = 160
Dividing both sides by 10:
y = 16
Now that we know the value of y, we can substitute it back into the equation for m∠2:
m∠2 = 8y + 8 = 8(16) + 8 = 128 + 8 = 136
Therefore, m∠2 is equal to 136 degrees.
thank you for the help :)
You're welcome! I'm glad I could help. If you have any more questions, feel free to ask.