Question

A satellite is orbiting Earth at an orbital radius of 3.9×103
m. What is its velocity in terms of G and the mass of Earth, mp? (Ignore units in the answer.)(1 point)
Responses

(1.6×10−2)Gmp−−−−√
open paren 1 point 6 times 10 to the negative 2 power close paren times square root of cap g m sub p end root

(3.9×103)Gmp−−−−√
open paren 3 point 9 times 10 cubed close paren times square root of cap g m sub p end root

(6.2×101)Gmp−−−−√
open paren 6 point 2 times 10 to the 1th power close paren times square root of cap g m sub p end root

(2.6×10−4)Gmp−−−−√

Answer 1

None of the given responses are correct. The correct expression for the velocity of a satellite in terms of G and the mass of Earth, mp, is:

(√(G * mp) / √(orbital radius))

Answer 2

Let G be the universal gravitational constant and mp be the mass of the planet a satellite is orbiting. Which equation could be used to find the velocity of the satellite if it is placed in a low Earth orbit?(1 point)
Responses

v=Gmp(7,000 km)−−−−−−−√
v=Gmp(7,000 km)−−−−−−−√

v=1(200 km)Gmp−−−−√
v=1(200 km)Gmp−−−−√

v=1(7,000 km)Gmp−−−−√
v=1(7,000 km)Gmp−−−−√

v=Gmp(200 km)−−−−−−√
v=Gmp(200 km)−−−−−−√

Answer 3

The correct equation to find the velocity of the satellite in a low Earth orbit is:

v = √(G * mp / r)

where r is the orbital radius. Therefore, the correct response is:

v = √(G * mp * 200 km)