A competitive cliff-diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t=2 by using the formula 75−16t2, where t is time in seconds.

Answer 1

To find the number of feet the diver is above the ocean in 2 seconds, we need to substitute t=2 into the formula 75-16t^2.

Plugging t=2 into the formula, we get:

75 - 16(2^2) = 75 - 16(4) = 75 - 64 = 11.

Therefore, the diver is 11 feet above the ocean in 2 seconds.