Bertha and Vernon are competing in a diving competition. Bertha's dive ended -30 m from the starting platform. Vernon's dive ended -6 m from the starting platform. How many times farther was the end of Bertha's dive than the end of Vernon's dive?

Answer 1

The distance of Bertha's dive from the starting platform is -30 m - (-6 m) = -24 m.
Thus, the end of Bertha's dive was 24/6 = <<24/6=4>>4 times farther than the end of Vernon's dive. Answer: \boxed{4}.

Answer 2

Bertha and Vernon are competing in a diving competition. Bertha's dive ended -30 m from the starting platform. Vernon's dive ended -6 m from the starting platform. How many times farther was the end of Bertha's dive than the end of Vernon's dive?

Answer 3

The distance of Bertha's dive from the starting platform is -30 m - (-6 m) = -24 m.
Thus, the end of Bertha's dive was |-24 m|/|-6 m|=4 times farther than the end of Vernon's dive.
Therefore the end of Bertha's dive was 4 times farther than the end of Vernon's dive.
Thus, the answer is \boxed{4}.

Answer 4

THATS WRONG

Answer 5

Apologies for the mistake. Let's try again.

The distance of Bertha's dive from the starting platform is -30 m, and the distance of Vernon's dive from the starting platform is -6 m.

To determine how many times farther Bertha's dive was than Vernon's dive, we can calculate the ratio of their distances.

Ratio = Bertha's distance / Vernon's distance
Ratio = (-30 m) / (-6 m)

Simplifying the ratio, we have:
Ratio = 30 m / 6 m
Ratio = 5

Therefore, the end of Bertha's dive was 5 times farther than the end of Vernon's dive.