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Bertha and Vernon are competing in a diving competition. Bertha's dive ended -30 m from the starting platform Vernon's dive end...Asked by Axel
Bertha and Vernon are competing in a diving competition. Bertha's dive ended -30 m from the starting platform. Vernon's dive ended -6 m from the starting platform. How many times farther was the end of Bertha's dive than the end of Vernon's dive?
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Answered by
GPT 3.5
The distance of Bertha's dive from the starting platform is -30 m - (-6 m) = -24 m.
Thus, the end of Bertha's dive was 24/6 = <<24/6=4>>4 times farther than the end of Vernon's dive. Answer: \boxed{4}.
Thus, the end of Bertha's dive was 24/6 = <<24/6=4>>4 times farther than the end of Vernon's dive. Answer: \boxed{4}.
Answered by
GPT 3.5
The distance of Bertha's dive from the starting platform is -30 m - (-6 m) = -24 m.
Thus, the end of Bertha's dive was |-24 m|/|-6 m|=4 times farther than the end of Vernon's dive.
Therefore the end of Bertha's dive was 4 times farther than the end of Vernon's dive.
Thus, the answer is \boxed{4}.
Thus, the end of Bertha's dive was |-24 m|/|-6 m|=4 times farther than the end of Vernon's dive.
Therefore the end of Bertha's dive was 4 times farther than the end of Vernon's dive.
Thus, the answer is \boxed{4}.
Answered by
GPT 3.5
Apologies for the mistake. Let's try again.
The distance of Bertha's dive from the starting platform is -30 m, and the distance of Vernon's dive from the starting platform is -6 m.
To determine how many times farther Bertha's dive was than Vernon's dive, we can calculate the ratio of their distances.
Ratio = Bertha's distance / Vernon's distance
Ratio = (-30 m) / (-6 m)
Simplifying the ratio, we have:
Ratio = 30 m / 6 m
Ratio = 5
Therefore, the end of Bertha's dive was 5 times farther than the end of Vernon's dive.
The distance of Bertha's dive from the starting platform is -30 m, and the distance of Vernon's dive from the starting platform is -6 m.
To determine how many times farther Bertha's dive was than Vernon's dive, we can calculate the ratio of their distances.
Ratio = Bertha's distance / Vernon's distance
Ratio = (-30 m) / (-6 m)
Simplifying the ratio, we have:
Ratio = 30 m / 6 m
Ratio = 5
Therefore, the end of Bertha's dive was 5 times farther than the end of Vernon's dive.
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