Question

Which of the following properly uses a polynomial identity to detect if 2^2k−1 is prime?

Answer 1

The proper use of a polynomial identity to detect if 2^2k−1 is prime is:

If 2^2k−1 can be factored as (2^k + 1)(2^k − 1), then it is not prime.

This is known as the difference of squares identity, where a^2 − b^2 = (a + b)(a − b). Therefore, if 2^2k−1 can be expressed as a difference of squares, it is not prime.

Answer 2

Identify the descending numerical order of these fractions and decimals: 0.733, 0.923, 1 2/5, 17/20, 15/18.(1 point)

Answer 3

The descending numerical order of the given fractions and decimals is:

1. 1 2/5
2. 17/20
3. 15/18
4. 0.923
5. 0.733

Answer 4

Calculate the decimal number for each fraction and identify the ascending numerical order of the decimal numbers:

5/8, 1/4, 3/8, 2/3, 6/7

(1 point)

Answer 5

To calculate the decimal number for each fraction, divide the numerator by the denominator:

5/8 = 0.625
1/4 = 0.25
3/8 = 0.375
2/3 = 0.666666... (rounded to 0.67)
6/7 = 0.857142857... (rounded to 0.86)

The ascending numerical order of the decimal numbers is:

1. 0.25
2. 0.375
3. 0.625
4. 0.67
5. 0.86

Answer 6

that's wrong and do it as fractions

Answer 7

Apologies for the confusion. Let's calculate the decimal number for each fraction by dividing the numerator by the denominator:

5/8 = 0.625
1/4 = 0.25
3/8 = 0.375
2/3 = 0.666666...
6/7 = 0.857142857...

Now let's identify the ascending numerical order of the fractions:

1. 1/4
2. 3/8
3. 5/8
4. 2/3
5. 6/7

Answer 8

wrong

Answer 9

Apologies for the incorrect response. Let's calculate the decimal numbers for each fraction:

5/8 = 0.625
1/4 = 0.25
3/8 = 0.375
2/3 ≈ 0.667
6/7 ≈ 0.857

Now let's identify the ascending numerical order of the decimal numbers:

1. 0.25 (1/4)
2. 0.375 (3/8)
3. 0.625 (5/8)
4. 0.667 (2/3)
5. 0.857 (6/7)