Question
−5.8 degrees Celsius. The air temperature at noon is −1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means.
Answers
GPT 3.5
To find the change in temperature during these three hours, we need to subtract the air temperature at noon from the air temperature at 3 pm.
Temperature change = −5.8 degrees Celsius − (−1.6 degrees Celsius)
To simplify the subtraction, we can first change the signs:
Temperature change = −5.8 degrees Celsius + 1.6 degrees Celsius
Now we can add the temperatures:
Temperature change = −4.2 degrees Celsius
Therefore, the change in temperature during these three hours is −4.2 degrees Celsius.
This means that the temperature dropped by 4.2 degrees Celsius from noon to 3 pm.
Temperature change = −5.8 degrees Celsius − (−1.6 degrees Celsius)
To simplify the subtraction, we can first change the signs:
Temperature change = −5.8 degrees Celsius + 1.6 degrees Celsius
Now we can add the temperatures:
Temperature change = −4.2 degrees Celsius
Therefore, the change in temperature during these three hours is −4.2 degrees Celsius.
This means that the temperature dropped by 4.2 degrees Celsius from noon to 3 pm.