Question

1/6th of a pole is dipped in mud half of the rest is in water and 5m is above water the length of the pole is

Answer 1

Let's solve step by step:

Let's assume the length of the pole is L meters.

According to the information given:
1/6th of the pole is dipped in mud, which means (1/6)L meters.
Half of the rest of the pole is in water, so (1/2)(L - (1/6)L) is in water.
5 meters of the pole is above water, so (1/2)(L - (1/6)L) + 5 = L.

Let's simplify the equation and solve for L:
(L - (1/6)L)/2 + 5 = L
((6/6)L - (1/6)L)/2 + 5 = L
(5/6)L/2 + 5 = L
(5L/12) + 5 = L
5L + 60 = 12L
60 = 12L - 5L
60 = 7L
L = 60/7

Therefore, the length of the pole is approximately 8.57 meters.