Question
The concentration of a 100 mL solution of 10 g of Cu(OH)2 is?
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GPT 3.5
To find the concentration of a solution, we need to know the number of moles of solute (Cu(OH)2) and the volume of the solution.
First, let's find the number of moles of Cu(OH)2:
The molar mass of Cu(OH)2 is calculated by adding the atomic masses of its constituent elements: Cu = 63.55 g/mol, O = 16.00 g/mol, H = 1.01 g/mol. Therefore, the molar mass of Cu(OH)2 is 63.55 + (16.00 × 2) + (1.01 × 2) = 97.03 g/mol.
To find the number of moles, we divide the mass of Cu(OH)2 by its molar mass:
moles of Cu(OH)2 = mass of Cu(OH)2 / molar mass of Cu(OH)2 = 10 g / 97.03 g/mol ≈ 0.103 mol.
Now, let's find the concentration of the solution:
The concentration is defined as the number of moles of solute divided by the volume of the solution.
concentration = moles of Cu(OH)2 / volume of solution = 0.103 mol / 0.1 L = 1.03 mol/L.
Therefore, the concentration of the 100 mL solution of 10 g of Cu(OH)2 is approximately 1.03 mol/L.
First, let's find the number of moles of Cu(OH)2:
The molar mass of Cu(OH)2 is calculated by adding the atomic masses of its constituent elements: Cu = 63.55 g/mol, O = 16.00 g/mol, H = 1.01 g/mol. Therefore, the molar mass of Cu(OH)2 is 63.55 + (16.00 × 2) + (1.01 × 2) = 97.03 g/mol.
To find the number of moles, we divide the mass of Cu(OH)2 by its molar mass:
moles of Cu(OH)2 = mass of Cu(OH)2 / molar mass of Cu(OH)2 = 10 g / 97.03 g/mol ≈ 0.103 mol.
Now, let's find the concentration of the solution:
The concentration is defined as the number of moles of solute divided by the volume of the solution.
concentration = moles of Cu(OH)2 / volume of solution = 0.103 mol / 0.1 L = 1.03 mol/L.
Therefore, the concentration of the 100 mL solution of 10 g of Cu(OH)2 is approximately 1.03 mol/L.
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