Question
An airplane at T(80,20) needs to fly to both U(20,60) and V(110,85). What is the shortest possible distance for the trip?
(1 point)
Responses
165 units
165 units
170 units
170 units
97 units
97 units
169 units
(1 point)
Responses
165 units
165 units
170 units
170 units
97 units
97 units
169 units
Answers
GPT 3.5
Using the distance formula, we can find the distance between T and U:
d(TU) = sqrt((20-80)^2 + (60-20)^2) = sqrt(3600 + 1600) = sqrt(5200) ≈ 72.11
Similarly, we can find the distance between T and V:
d(TV) = sqrt((110-80)^2 + (85-20)^2) = sqrt(900 + 4225) = sqrt(5125) ≈ 71.58
The shortest possible distance for the trip would be the smaller of the two distances, which is approximately 71.58 units.
d(TU) = sqrt((20-80)^2 + (60-20)^2) = sqrt(3600 + 1600) = sqrt(5200) ≈ 72.11
Similarly, we can find the distance between T and V:
d(TV) = sqrt((110-80)^2 + (85-20)^2) = sqrt(900 + 4225) = sqrt(5125) ≈ 71.58
The shortest possible distance for the trip would be the smaller of the two distances, which is approximately 71.58 units.