Asked by spider

The town of Oak Manor measures 3.8 miles by 4.2 miles. Solve for the total area.(1 point)
Responses

15.96 mi
15.96 mi

15.96 mi2
15.96 mi squared

8 mi2
8 mi squared

16 mi2.
Answered by spider
A diver searches for a sunken treasure that is 97.2
feet below the surface. What is the diver's elevation when he is 23 of the way down? (1 point)
Responses

−32.4
ft.
negative 32 point 4 ft.

−145.8 ft.
negative 145 point 8 ft.

−64.8
ft.
negative 64 point 8 ft.

−48.5
ft.
Answered by spider
A basketball player is 623 feet tall. His infant son is 14 as tall. How tall is his son?(1 point)
Responses

1 1/2 ft.
1 Start Fraction 1 over 2 End Fraction ft.

2 2/3 ft.
2 Start Fraction 2 over 3 End Fraction ft.

2 2/12 ft.
2 Start Fraction 2 over 12 End Fraction ft.

1 2/3 ft.
Answered by GPT 3.5
To solve for the total area, you need to multiply the length and the width of the town of Oak Manor.

So, the total area is 3.8 miles x 4.2 miles = 15.96 square miles.

Therefore, the correct answer is 15.96 mi2 or 15.96 mi squared.
Answered by GPT 3.5
To find the diver's elevation when he is 23% of the way down, you need to find 23% of 97.2 ft.

23% of 97.2 ft = 0.23 * 97.2 ft = 22.356 ft.

Therefore, the diver's elevation when he is 23% of the way down is -22.356 ft, which can be rounded to -22.4 ft or -22.4 feet above sea level.

None of the provided options match the correct answer.
Answered by GPT 3.5
If the basketball player is 623 feet tall and his infant son is 1/4 as tall, we need to find 1/4 of 623 feet.

1/4 of 623 feet = (1/4) * 623 feet = 155.75 feet.

Therefore, the son is 155.75 feet tall.

None of the provided options match the correct answer.