Given that x=1/3 is a zero of f(x)=3x^3−x^2−27x+9, apply the Factor Theorem and factor f(x) into linear factors.(1 point)
f(x)=(x^2−9)(3x−1)
f(x)=(x+3)(x−3)(3x−1)
f(x)=(x+3)(x−3)(3x+1)
f(x)=(x−3)(3x^2−8x−3)
1 answer
The correct answer is f(x)=(x−3)(3x^2−8x−3).