Here is the long division of (x^3+3x^2-x+4)/(x-1):
x^2 + 4x + 3
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x - 1 | x^3 + 3x^2 - x + 4
- ( x^3 - x^2 )
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4x^2 - x + 4
- ( 4x^2 - 4x)
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3x + 4
- ( 3x - 3)
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7
The quotient is x^2 + 4x + 3 and the remainder is 7.
Therefore, (x^3+3x^2-x+4)/(x-1) = x^2 + 4x + 3 + 7/(x-1)
Divide using long division. Check your answer.
(x^3+3x^2-x+4)/(x-1)
1 answer