2K + 2H2O---->2KOH+some amount of H2

Question

2
4
6
8

Answer 1

The balanced equation for the given reaction is:

2K + 2H2O -> 2KOH + H2

This means that for every 2 moles of potassium (K) and 2 moles of water (H2O) used in the reaction, 2 moles of potassium hydroxide (KOH) and 1 mole of hydrogen gas (H2) are produced.

Therefore, the amount of H2 produced is 1 mole.