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A third ant walks around the perimeter of another rectangle sheet of paper. The dimensions of this sheet of paper are given in...Question
4. A third ant walks around the perimeter of another rectangular sheet of
paper. The dimensions of this sheet of paper are given in decimal
numbers expressed to the hundredth place, with the tenths and
hundredths digits being non-zero. If the ant travels between 18 and 19
centimeters, what are the dimensions of the sheet of paper? Give one
possibility.
paper. The dimensions of this sheet of paper are given in decimal
numbers expressed to the hundredth place, with the tenths and
hundredths digits being non-zero. If the ant travels between 18 and 19
centimeters, what are the dimensions of the sheet of paper? Give one
possibility.
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Answered by
GPT 3.5
Let's assume one dimension of the rectangular sheet of paper is x centimeters and the other dimension is y centimeters.
When the ant walks around the perimeter of the rectangular sheet of paper, it covers a distance equal to 2x + 2y centimeters.
We are given that the ant travels between 18 and 19 centimeters, so we can write the inequality as follows:
18 < 2x + 2y < 19
Dividing the entire inequality by 2, we get:
9 < x + y < 9.5
Since x and y are decimal numbers expressed to the hundredth place, we need to find two numbers whose sum is between 9 and 9.5.
One possibility is x = 4.50 and y = 4.50. In this case, x + y = 4.50 + 4.50 = 9, which is between 9 and 9.5.
So, one possibility for the dimensions of the sheet of paper is 4.50 cm by 4.50 cm.
When the ant walks around the perimeter of the rectangular sheet of paper, it covers a distance equal to 2x + 2y centimeters.
We are given that the ant travels between 18 and 19 centimeters, so we can write the inequality as follows:
18 < 2x + 2y < 19
Dividing the entire inequality by 2, we get:
9 < x + y < 9.5
Since x and y are decimal numbers expressed to the hundredth place, we need to find two numbers whose sum is between 9 and 9.5.
One possibility is x = 4.50 and y = 4.50. In this case, x + y = 4.50 + 4.50 = 9, which is between 9 and 9.5.
So, one possibility for the dimensions of the sheet of paper is 4.50 cm by 4.50 cm.
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