Solve the system. 7×+2y=-8; 8y=4×

Answer 1

To solve the system, let's rearrange the equations:

Equation 1: 7x + 2y = -8

Equation 2: 4x - 8y = 0 (divided both sides by 4)

Next, let's multiply Equation 1 by 4 to eliminate the coefficient of x in equation 2:

4(7x + 2y) = 4(-8)
28x + 8y = -32

Now we have two equations with the same coefficient in x:

Equation 3: 28x + 8y = -32
Equation 2: 4x - 8y = 0

By adding Equation 3 and Equation 2:

(28x + 8y) + (4x - 8y) = -32 + 0
32x = -32

Divide by 32 on both sides of the equation:

x = -32/32
x = -1

Now substitute x = -1 into either equation to solve for y. Let's use Equation 2:

8y = 4(-1)
8y = -4

Divide both sides by 8:

y = -4/8
y = -1/2

Therefore, the solution to the system of equations is x = -1 and y = -1/2.