Solve the system. 3a+4b=9; -3a-2b=-3

Answer 1

To solve the system of equations, we can use the method of elimination. By adding the two equations together, we can eliminate the variable a:

(3a + 4b) + (-3a - 2b) = 9 + (-3)
3a - 3a + 4b - 2b = 6
2b = 6
b = 3

Now that we have the value of b, we can substitute it back into one of the original equations to find the value of a:

3a + 4(3) = 9
3a + 12 = 9
3a = 9 - 12
3a = -3
a = -1

Therefore, the solution to the system of equations is a = -1, b = 3.