Asked by elle
hey, i'd really appreciate some help differentiating this equation:
t= (4+x^2)^(1/2) /3 + (3-x)/5
so that's four plus x to the power of 2 all to the power of 1/2 all over three plus 3-x divided by five... :P
Thankyou.
I would rewrite it as
t= (1/3)(4+x^2)^(1/2) + 3/5 - (1/5)x
then
dt/dx = (1/6)(4+x^2)^(-1/2)(2x) - 1/5
=(1/3)x((4+x^2)^(-1/2) - 1/5
At this point, further simplification could be done, depending on the demands of the teacher or the textbook.
t= (4+x^2)^(1/2) /3 + (3-x)/5
so that's four plus x to the power of 2 all to the power of 1/2 all over three plus 3-x divided by five... :P
Thankyou.
I would rewrite it as
t= (1/3)(4+x^2)^(1/2) + 3/5 - (1/5)x
then
dt/dx = (1/6)(4+x^2)^(-1/2)(2x) - 1/5
=(1/3)x((4+x^2)^(-1/2) - 1/5
At this point, further simplification could be done, depending on the demands of the teacher or the textbook.
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