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a third ant walks around the perimeter of another rectangular sheet of paper the dimension of this sheet of paper are given in...Asked by pls help
A third ant walks around the perimeter of another rectangular sheet of paper. The dimensions of this sheet of paper are given in decimal numbers expressed to the hundredth place, with the tenths and hundredths digits being non-zero. If the ant travels between 18 and 19 centimeters, what are the dimensions of the sheet of paper? Give one possibility. im confused and i need help
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Let's assume the length of the paper is $L$ and the width is $W$.
Since the ant walks around the perimeter of the paper, the distance it travels is equal to the sum of all four sides of the paper.
We can express this distance as $2L + 2W$.
We are told that this distance is between 18 and 19 centimeters, so we can write the inequality:
$18 < 2L + 2W < 19$
Dividing both sides of the inequality by $2$, we get:
$9 < L + W < \frac{19}{2}$
Since the dimensions are given in decimal numbers expressed to the hundredth place, with the tenths and hundredths digits being non-zero, we can assume that $L$ and $W$ are slightly less than $\frac{19}{2}$.
For example, let's assume $L = 9.45$ and $W = 0.55$.
The sum of the two dimensions is $L + W = 10$ which is between $9$ and $\frac{19}{2}$.
Hence, one possibility for the dimensions of the sheet of paper is $9.45$ cm by $0.55$ cm.
Since the ant walks around the perimeter of the paper, the distance it travels is equal to the sum of all four sides of the paper.
We can express this distance as $2L + 2W$.
We are told that this distance is between 18 and 19 centimeters, so we can write the inequality:
$18 < 2L + 2W < 19$
Dividing both sides of the inequality by $2$, we get:
$9 < L + W < \frac{19}{2}$
Since the dimensions are given in decimal numbers expressed to the hundredth place, with the tenths and hundredths digits being non-zero, we can assume that $L$ and $W$ are slightly less than $\frac{19}{2}$.
For example, let's assume $L = 9.45$ and $W = 0.55$.
The sum of the two dimensions is $L + W = 10$ which is between $9$ and $\frac{19}{2}$.
Hence, one possibility for the dimensions of the sheet of paper is $9.45$ cm by $0.55$ cm.
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