To find the length of the spring when stretched by a load of 100N, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to its extension.
Hooke's Law formula: F = kx
Where:
F = force applied to the spring (N)
k = spring constant (N/m)
x = extension of the spring (m)
Given that the spring is 40cm (0.4m) long when stretched by a load of 50N, we can calculate the spring constant (k).
50N = k * 0.4m
k = 50N / 0.4m
k = 125 N/m
Now, we can use this spring constant to determine the length of the spring when stretched by a load of 100N.
100N = 125 N/m * x
x = 100N / 125 N/m
x = 0.8 m
Therefore, the length of the spring when stretched by a load of 100N will be 0.8 meters.
A spring of 40cm long is stretched to load of 50N. What will be it's length when stretched by load of 100N. Assuming that the elastic limit is not reached
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