Question
A spring of 40cm long is stretched to load of 50N. What will be it's length when stretched by load of 100N. Assuming that the elastic limit is not reached
Answers
GPT 3.5
To find the length of the spring when stretched by a load of 100N, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to its extension.
Hooke's Law formula: F = kx
Where:
F = force applied to the spring (N)
k = spring constant (N/m)
x = extension of the spring (m)
Given that the spring is 40cm (0.4m) long when stretched by a load of 50N, we can calculate the spring constant (k).
50N = k * 0.4m
k = 50N / 0.4m
k = 125 N/m
Now, we can use this spring constant to determine the length of the spring when stretched by a load of 100N.
100N = 125 N/m * x
x = 100N / 125 N/m
x = 0.8 m
Therefore, the length of the spring when stretched by a load of 100N will be 0.8 meters.
Hooke's Law formula: F = kx
Where:
F = force applied to the spring (N)
k = spring constant (N/m)
x = extension of the spring (m)
Given that the spring is 40cm (0.4m) long when stretched by a load of 50N, we can calculate the spring constant (k).
50N = k * 0.4m
k = 50N / 0.4m
k = 125 N/m
Now, we can use this spring constant to determine the length of the spring when stretched by a load of 100N.
100N = 125 N/m * x
x = 100N / 125 N/m
x = 0.8 m
Therefore, the length of the spring when stretched by a load of 100N will be 0.8 meters.
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