Question

The sum of three consecutive even integers (3 even integers in a row) is 120.
Use the following setup and given equation to find your solution:

1st integer = x
2nd integer = x+2
3rd integer = x+4
Equation: x+(x+2)+(x+4)=120

Solve the equation above. What is the largest of the three integers?

42

38

44

38, 42, 44

Answer 1

To solve the given equation, we need to combine like terms and solve for x:

x + (x+2) + (x+4) = 120

Combine like terms:

3x + 6 = 120

Subtract 6 from both sides:

3x = 114

Divide both sides by 3:

x = 38

The largest of the three integers is x+4:

38 + 4 = 42

Therefore, the largest of the three integers is 42.