Asked by Ur Woman ^o^

Use long division to convert 27/50 to a decimal.(1 point)
Responses

0.54
0.54

5.4
5.4

1.851
1.851

27.5
Answered by Ur Woman ^o^
Use long division to convert 3 3/8 to a decimal.(1 point)

Responses

33.75

33.75

2.66

2.66

3.375

3.375

0.375
Answered by Ur Woman ^o^
Use long division to convert 4/15 to a decimal.(1 point)
Responses

26
26

3.75
3.75

4.15
4.15

≈0.27
Answered by Ur Woman ^o^
Use long division to convert 7/11 to a decimal.(1 point)
Responses

63
63

7.11
7.11

≈0.63
approximately equals 0.63

≈1.571428
Answered by Ur Woman ^o^
Use long division to convert 5 3/16 to a decimal.(1 point)
Responses

0.1875
0.1875

5.36
5.36

5.1875
5.1875

≈5.3
Answered by Ur Woman ^o^
Thx Bot
Answered by Ur Woman ^o^
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Answered by Ur Woman ^o^
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Answered by Ur Woman ^o^
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Answered by Ur Woman ^o^
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Answered by Ur Woman ^o^
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Answered by yourmommaisthicc
are all of these answers correct?
Answered by my roblox is 38k_jaden14
A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel’s height above the ground. Give your answer to the nearest hundredth.(1 point)
Responses

The quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.

The quotient that describes the rate of change in the squirrel’s height above the ground is 19.05 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 19.05 feet/second.

The quotient that describes the rate of change in the squirrel’s height above the ground is −19.05 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is negative 19.05 feet/second.

The quotient that describes the rate of change in the squirrel’s height above the ground is −10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is negative 10.48 feet/second.
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Answered by yellow❁sunny
thank, u bot, my name is yellow sunny
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