Question

Here are the high temperatures (in Fahrenheit) for a 10-day period in Salinas, California, in December:

58, 59, 61, 62, 62, 62, 63, 64, 66, 67

Find the range and explain what the value means for this dataset.

(2 points)
The range is
degrees Fahrenheit; this is the difference in degrees Fahrenheit between
degrees, the minimum temperature, and
degrees, the maximum

Answer 1

Here are the science test scores from Ms. O’Donnell’s class:

55, 60, 70, 70, 75, 75, 75, 80, 80, 85, 85, 85, 85, 90, 90, 95, 100

Find the MAD.

(1 point)
The MAD is
.

Answer 2

Its wrong

Answer 3

temperature. The range for this dataset is 9 degrees Fahrenheit; this means that the highest temperature during this period was 67 degrees Fahrenheit and the lowest temperature was 58 degrees Fahrenheit.

Answer 4

To find the Mean Absolute Deviation (MAD), we need to first find the mean of the data set.

Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100)/ 17

Mean = 1355/17

Mean ≈ 79.71

Next, we find the absolute deviation for each score by subtracting the mean from each score and taking the absolute value:

|55 - 79.71| = 24.71
|60 - 79.71| = 19.71
|70 - 79.71| = 9.71
|70 - 79.71| = 9.71
|75 - 79.71| = 4.71
|75 - 79.71| = 4.71
|75 - 79.71| = 4.71
|80 - 79.71| = 0.29
|80 - 79.71| = 0.29
|85 - 79.71| = 5.29
|85 - 79.71| = 5.29
|85 - 79.71| = 5.29
|85 - 79.71| = 5.29
|90 - 79.71| = 10.29
|90 - 79.71| = 10.29
|95 - 79.71| = 15.29
|100 - 79.71| = 20.29

Next, we find the mean of the absolute deviations:

MAD = (24.71 + 19.71 + 9.71 + 9.71 + 4.71 + 4.71 + 4.71 + 0.29 + 0.29 + 5.29 + 5.29 + 5.29 + 5.29 + 10.29 + 10.29 + 15.29 + 20.29)/ 17

MAD = 144.71/17

MAD ≈ 8.51

Therefore, the Mean Absolute Deviation (MAD) is approximately 8.51.

Answer 5

Apologies for the error. Let's calculate the Mean Absolute Deviation (MAD) correctly.

To calculate the MAD, we need to find the deviation of each score from the mean, take the absolute value of each deviation, and then find the mean of those absolute deviations.

First, let's find the mean of the data set:
Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17
Mean = 1410 / 17
Mean ≈ 82.94

Next, calculate the deviation for each score by subtracting the mean from each score:
|55 - 82.94| = 27.94
|60 - 82.94| = 22.94
|70 - 82.94| = 12.94
|70 - 82.94| = 12.94
|75 - 82.94| = 7.94
|75 - 82.94| = 7.94
|75 - 82.94| = 7.94
|80 - 82.94| = 2.94
|80 - 82.94| = 2.94
|85 - 82.94| = 2.06
|85 - 82.94| = 2.06
|85 - 82.94| = 2.06
|85 - 82.94| = 2.06
|90 - 82.94| = 7.06
|90 - 82.94| = 7.06
|95 - 82.94| = 12.06
|100 - 82.94| = 17.06

Now, find the mean of the absolute deviations:
MAD = (27.94 + 22.94 + 12.94 + 12.94 + 7.94 + 7.94 + 7.94 + 2.94 + 2.94 + 2.06 + 2.06 + 2.06 + 2.06 + 7.06 + 7.06 + 12.06 + 17.06) / 17
MAD = 187.68 / 17
MAD ≈ 11.04

Therefore, the Mean Absolute Deviation (MAD) is approximately 11.04.