Canned juice A is 25% orange juice, while canned juice B is 5% orange juice. How many liters of juice A should be used mixed with juice B in order to get 10 L that is 24% orange juice?

Answer 1

Let x be the number of liters of juice A and y be the number of liters of juice B.
We have the equation x + y = 10 because the total amount of juice should be 10 L.
We also have the equation 0.25x + 0.05y = 0.24 * 10 because the total amount of orange juice should be 24% of the total amount of juice.
Simplifying the second equation, we get 0.25x + 0.05y = 2.4.
Multiplying both sides of the first equation by 0.05 to eliminate y, we get 0.05x + 0.05y = 0.5.
Subtracting the second equation from the first equation, we get 0.2x = 1.9.
Dividing both sides of the equation by 0.2, we get x = 9.5.
Substituting this value back into the first equation, we get 9.5 + y = 10.
Subtracting 9.5 from both sides of the equation, we get y = 0.5.
Therefore, 9.5 liters of juice A should be used mixed with 0.5 liters of juice B to get 10 L that is 24% orange juice.