To find the rate of change in the squirrel's height above the ground, we divide the change in height by the time it takes to make that change.
The change in height is 100 - 45 = 55 feet.
The time it takes to make this change is 5.25 seconds.
So, the rate of change in the squirrel's height can be calculated as:
55 feet / 5.25 seconds = 10.48 feet/second.
Rounded to the nearest hundredth, the rate of change in the squirrel's height above the ground is approximately 10.48 feet/second.
A squirrel has stored its acorns in a hole that
is 45 feet from the ground in tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored Acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel's height above the ground. Give your answer to the nearest hundredth.
2 answers
The quotient that describes the rate of change in the squirrel’s height above the ground is −10.48 feet/second.