To solve for x, we need to isolate the variable on one side of the equation.
Let's start by getting rid of the -10 on the right side of the equation by subtracting it from both sides:
4x + 8 - 10 = 3x - 10 - 10
Simplifying both sides:
4x - 2 = 3x - 20
Next, let's get rid of the 3x on the right side by subtracting 3x from both sides:
4x - 2 - 3x = 3x - 20 - 3x
Simplifying:
x - 2 = -20
Finally, we can isolate x by adding 2 to both sides of the equation:
x - 2 + 2 = -20 + 2
Simplifying gives us the final answer:
x = -18
Solve for x: 4x+8=3x−10.
9 answers
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Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other is already filled with 10 gallons, and it is continuing to fill at a rate of 4 gallons per minute. Write an equation to show when the two vats will have an equal amount of liquid. Use x as your variable. (1 point)
Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other is already filled with 10 gallons, and it is continuing to fill at a rate of 4 gallons per minute. Write an equation to show when the two vats will have an equal amount of liquid. Use x as your variable. (1 point)
Let's write an equation to represent the situation:
The first vat is empty and filling at a rate of 6 gallons per minute, so its liquid level can be represented as 6x, where x is the number of minutes.
The second vat is already filled with 10 gallons and filling at a rate of 4 gallons per minute, so its liquid level can be represented as 10 + 4x.
To find when the two vats will have an equal amount of liquid, we can set up the equation:
6x = 10 + 4x
Now, we can solve for x by subtracting 4x from both sides of the equation:
6x - 4x = 10 + 4x - 4x
2x = 10
Finally, we can solve for x by dividing both sides of the equation by 2:
2x/2 = 10/2
x = 5
Therefore, the two vats will have an equal amount of liquid after 5 minutes.
The first vat is empty and filling at a rate of 6 gallons per minute, so its liquid level can be represented as 6x, where x is the number of minutes.
The second vat is already filled with 10 gallons and filling at a rate of 4 gallons per minute, so its liquid level can be represented as 10 + 4x.
To find when the two vats will have an equal amount of liquid, we can set up the equation:
6x = 10 + 4x
Now, we can solve for x by subtracting 4x from both sides of the equation:
6x - 4x = 10 + 4x - 4x
2x = 10
Finally, we can solve for x by dividing both sides of the equation by 2:
2x/2 = 10/2
x = 5
Therefore, the two vats will have an equal amount of liquid after 5 minutes.
I recently saw this picture of a girl/lady wearing some metal thing to cover her breasts but the sides of the breasts peeking out and she wore an metal type underwear but it was not underwear to cover her butt and front side and she had big bumps of bone sticking out so that the metal thing that covered her parts could go very far done only a couple inches how does she go to the bathroom
The description you provided seems to refer to a specific outfit or costume, possibly from a movie, show, or event. The functionality and design of such outfits can vary depending on their purpose and creative choices. In some cases, the outfit may be designed to be easily removed or adjusted for bathroom use. However, without more specific information about the outfit or its purpose, it is difficult to provide further details.
No I saw the lady too it was one hole piece on her she said she was wearing it then the bone stuck out
Apologies for the confusion, but without further details or context, it is challenging to determine the specific functional design of the outfit you are referring to. Outfits and costumes can greatly vary in their design and functionality, and it's possible that the specific outfit you saw is specifically designed to be visible in certain areas while still maintaining coverage in others. The functionality of bathroom usage would depend on the specific construction and design of the outfit, which is not clear from the description given.
But what if she couldn't take it off only down a couple inches how does she go to the bathroom
If the outfit you are referring to does not allow for easy removal and only has a limited range of movement, it could potentially pose challenges when it comes to bathroom use. In such cases, individuals wearing such outfits might need to find creative solutions, such as using a specially designed attachment or opening in the outfit, or seeking assistance from someone else to help with the process. However, without more specific information about the outfit in question, it is difficult to provide a more detailed answer.