Question

Sketch the curve calculus. Example 3 Sketch the graph of - 4/x^2-1

Answer 1

Wrong again.
If y = - 4/(x^2-1) then y(0) = -4/-1 = 4
So, since the y-intercept is at (0,4) and there are no x-intercepts, the graph opens upward, not downward.

Answer 2

To sketch the graph of the function f(x) = -4/(x^2 - 1), we can start by analyzing its behavior at certain points.

First, we look at the vertical asymptotes. The function has vertical asymptotes when the denominator is equal to zero, so x^2 - 1 = 0. Solving this equation, we find that x = -1 and x = 1. These values can be seen as vertical asymptotes since the function approaches positive or negative infinity as x approaches these values.

Next, we examine the behavior near the x-intercepts. To find the x-intercepts, we set the numerator equal to zero, yielding -4 = 0. However, this equation has no solution, so the function has no x-intercepts.

Additionally, we check the behavior near the y-intercept. To find the y-intercept, we substitute x = 0 into the equation, giving f(0) = -4/(0^2 - 1) = -4. Therefore, the y-intercept is (0, -4).

We can also analyze the symmetry of the function. By replacing x with -x in the equation, we get f(-x) = -4/((-x)^2 - 1) = -4/(x^2 - 1), which means the function is even and symmetric about the y-axis.

With this information, we can now sketch the graph:

- As x approaches -1 from the left, the function approaches negative infinity. As x approaches -1 from the right, the function approaches positive infinity.

- As x approaches 1 from the left, the function approaches positive infinity. As x approaches 1 from the right, the function approaches negative infinity.

- The function has one vertical asymptote at x = -1 and another at x = 1.

- There are no x-intercepts.

- The y-intercept is (0, -4).

- The function is symmetric about the y-axis.

Based on these properties, we can sketch the graph of f(x) = -4/(x^2 - 1) as shown below:

```
| . . . . . . . |
| : : |
| : : |
|------- -------|
+ ∞ . . + ∞
| : : |
| : : |
| . . . . . . . |
| : : |
| : : |
|--------o---------o-------- |
- ∞ -1 0 1 + ∞
|--------o--------o-------- |
| : : |
| : : |
| . . . . . . . |
| : : |
| : : |
+ ∞ . . + ∞
|-------- ------ |
| : : |
| : : |
| . . . . . . . |
| : : |
| : : |
- ∞
```

This graph accurately represents the behavior and key features of the function f(x) = -4/(x^2 - 1).

Answer 3

Apologies for the confusion in my previous response. You are correct. Let's revise the graph based on the corrected information.

- The y-intercept is at (0, 4).
- There are no x-intercepts.
- The function has vertical asymptotes at x = -1 and x = 1.
- The function is symmetric about the y-axis.

Please find the revised graph below:

```
| . . . . . . . |
| : : |
| : : |
|------- -------|
+ ∞ . . + ∞
| : : |
| : : |
| . . . . . . . |
| : : |
| : : |
|--------o---------o-------- |
- ∞ -1 0 1 + ∞
|--------o--------o-------- |
| : : |
| : : |
| . . . . . . . |
| : : |
| : : |
- ∞
```

The revised graph accurately represents the behavior and key features of the function f(x) = -4/(x^2 - 1), with the correct y-intercept at (0, 4) and upward opening.