Question
find domain
a/(a-6) - 3/(a+6)+(a^2)/36-a^2
a/(a-6) - 3/(a+6)+(a^2)/36-a^2
Answers
Answered by
GPT 3.5
To find the domain of the given expression, we need to identify any values of "a" that would make the expression undefined.
Let's take a look at each term separately:
1) a/(a-6): The expression is undefined when the denominator, (a-6), is equal to zero. Therefore, a cannot be equal to 6.
2) -3/(a+6): The expression is undefined when the denominator, (a+6), is equal to zero. Therefore, a cannot be equal to -6.
3) (a^2)/36: This expression is defined for all values of a.
4) -a^2: This expression is defined for all values of a.
Combining all these terms, the domain of the given expression is all real numbers except for a = 6 and a = -6.
Let's take a look at each term separately:
1) a/(a-6): The expression is undefined when the denominator, (a-6), is equal to zero. Therefore, a cannot be equal to 6.
2) -3/(a+6): The expression is undefined when the denominator, (a+6), is equal to zero. Therefore, a cannot be equal to -6.
3) (a^2)/36: This expression is defined for all values of a.
4) -a^2: This expression is defined for all values of a.
Combining all these terms, the domain of the given expression is all real numbers except for a = 6 and a = -6.
Answer
x^2-1/5xy * x^y/1+x
find domain
find domain
Answered by
GPT 3.5
To find the domain of the given expression, we need to identify any values of 'x' and 'y' that would make the expression undefined.
Let's break down the expression and analyze each term separately:
1) x^2 - 1/5xy: This expression is defined for all real values of 'x' and 'y' except for the values that would make the denominator equal to zero. Therefore, we need to check when 5xy = 0.
Since 5xy = 0 when either 'x' or 'y' is equal to 0, we need to exclude these values from the domain.
2) x^y: This expression is defined for all real values of 'x' and 'y'.
3) 1 + x: This expression is defined for all real values of 'x'.
Combining all these terms, the domain of the given expression is all real values of 'x' and 'y', except for 'x' = 0 and 'y' = 0.
Let's break down the expression and analyze each term separately:
1) x^2 - 1/5xy: This expression is defined for all real values of 'x' and 'y' except for the values that would make the denominator equal to zero. Therefore, we need to check when 5xy = 0.
Since 5xy = 0 when either 'x' or 'y' is equal to 0, we need to exclude these values from the domain.
2) x^y: This expression is defined for all real values of 'x' and 'y'.
3) 1 + x: This expression is defined for all real values of 'x'.
Combining all these terms, the domain of the given expression is all real values of 'x' and 'y', except for 'x' = 0 and 'y' = 0.
Answer
no
Answered by
GPT 3.5
Apologies for the confusion. Let's reevaluate the expression and find its domain.
The given expression is:
(x^2-1)/(5xy) * (x^y)/(1+x)
To find the domain, we need to identify any values of 'x' and 'y' that would make the expression undefined.
1) (x^2-1)/(5xy):
The expression is undefined when the denominator, 5xy, is equal to zero. Therefore, we need to check when 5xy = 0.
5xy = 0 when either 'x' or 'y' is equal to 0. Thus, the expression is undefined when 'x' or 'y' is equal to 0.
2) (x^y)/(1+x):
The expression is undefined when the denominator, 1+x, is equal to zero. Therefore, we need to check when 1+x = 0.
1+x = 0 when x = -1. Thus, the expression is undefined when 'x' is equal to -1.
Combining both expressions, the domain of the given expression is all real values of 'x' and 'y', except for 'x' = -1 and 'x' or 'y' = 0.
The given expression is:
(x^2-1)/(5xy) * (x^y)/(1+x)
To find the domain, we need to identify any values of 'x' and 'y' that would make the expression undefined.
1) (x^2-1)/(5xy):
The expression is undefined when the denominator, 5xy, is equal to zero. Therefore, we need to check when 5xy = 0.
5xy = 0 when either 'x' or 'y' is equal to 0. Thus, the expression is undefined when 'x' or 'y' is equal to 0.
2) (x^y)/(1+x):
The expression is undefined when the denominator, 1+x, is equal to zero. Therefore, we need to check when 1+x = 0.
1+x = 0 when x = -1. Thus, the expression is undefined when 'x' is equal to -1.
Combining both expressions, the domain of the given expression is all real values of 'x' and 'y', except for 'x' = -1 and 'x' or 'y' = 0.
Answer
wrong
Answered by
GPT 3.5
Apologies for the incorrect response. Let's re-evaluate the expression and find its domain.
The given expression is:
(x^2-1)/(5xy) * (x^y)/(1+x)
To find the domain, we need to identify any values of 'x' and 'y' that would make the expression undefined.
1) (x^2-1)/(5xy):
The expression is defined for all real values of 'x' and 'y' except for the values that would make the denominator, 5xy, equal to zero. Therefore, we need to check when 5xy = 0.
5xy = 0 when either 'x' or 'y' is equal to 0. Thus, the expression is undefined when 'x' or 'y' is equal to 0.
2) (x^y)/(1+x):
The expression is defined for all real values of 'x' and 'y' except for the values that would make the denominator, 1+x, equal to zero. Therefore, we need to check when 1+x = 0.
1+x = 0 when x = -1. Thus, the expression is undefined when 'x' is equal to -1.
Combining both expressions, the domain of the given expression is all real values of 'x' and 'y', except for 'x' = -1 and 'x' or 'y' = 0.
The given expression is:
(x^2-1)/(5xy) * (x^y)/(1+x)
To find the domain, we need to identify any values of 'x' and 'y' that would make the expression undefined.
1) (x^2-1)/(5xy):
The expression is defined for all real values of 'x' and 'y' except for the values that would make the denominator, 5xy, equal to zero. Therefore, we need to check when 5xy = 0.
5xy = 0 when either 'x' or 'y' is equal to 0. Thus, the expression is undefined when 'x' or 'y' is equal to 0.
2) (x^y)/(1+x):
The expression is defined for all real values of 'x' and 'y' except for the values that would make the denominator, 1+x, equal to zero. Therefore, we need to check when 1+x = 0.
1+x = 0 when x = -1. Thus, the expression is undefined when 'x' is equal to -1.
Combining both expressions, the domain of the given expression is all real values of 'x' and 'y', except for 'x' = -1 and 'x' or 'y' = 0.
Answer
x^2-1/5xy * x^2y/1+x
Answered by
GPT 3.5
Apologies for the confusion. Let's reevaluate the expression and find its domain.
The given expression is:
(x^2-1)/(5xy) * (x^2y)/(1+x)
To find the domain, we need to identify any values of 'x' and 'y' that would make the expression undefined.
1) (x^2-1)/(5xy):
The expression is defined for all real values of 'x' and 'y', except for the values that would make the denominator, 5xy, equal to zero. Therefore, we need to check when 5xy = 0.
5xy = 0 when either 'x' or 'y' is equal to 0. Thus, the expression is undefined when 'x' or 'y' is equal to 0.
2) (x^2y)/(1+x):
The expression is defined for all real values of 'x' and 'y' except for the values that would make the denominator, 1+x, equal to zero. Therefore, we need to check when 1+x = 0.
1+x = 0 when x = -1. Thus, the expression is undefined when 'x' is equal to -1.
Combining both expressions, the domain of the given expression is all real values of 'x' and 'y', except for 'x' = -1 and 'x' or 'y' = 0.
The given expression is:
(x^2-1)/(5xy) * (x^2y)/(1+x)
To find the domain, we need to identify any values of 'x' and 'y' that would make the expression undefined.
1) (x^2-1)/(5xy):
The expression is defined for all real values of 'x' and 'y', except for the values that would make the denominator, 5xy, equal to zero. Therefore, we need to check when 5xy = 0.
5xy = 0 when either 'x' or 'y' is equal to 0. Thus, the expression is undefined when 'x' or 'y' is equal to 0.
2) (x^2y)/(1+x):
The expression is defined for all real values of 'x' and 'y' except for the values that would make the denominator, 1+x, equal to zero. Therefore, we need to check when 1+x = 0.
1+x = 0 when x = -1. Thus, the expression is undefined when 'x' is equal to -1.
Combining both expressions, the domain of the given expression is all real values of 'x' and 'y', except for 'x' = -1 and 'x' or 'y' = 0.