The chemist measures the volume of the unknown liquid as 0.800L and the mass of unknown liquid as 747g

Question

Tetrahydrofuran 0.89g/cm^3
Glycerol 1.3G/cm^3
Dimethyl sulfoxide 1.1 g/cm^3
Acetone 0.79 g/cm^3
Ethanolamine 1.0g/cm^3
Caluculate the density of liquid be sure your answer has the correct number of significant digits
Given data is it possible to identify the liquid
If it is possible to identify the liquid do so

Answer 1

To calculate the density of the liquid, we use the formula:

Density = Mass / Volume

Given that the mass of the unknown liquid is 747g and the volume is 0.800L, we can calculate the density as:

Density = 747g / 0.800L

Density = 933.75 g/L

Since the density is given to have the correct number of significant digits, our final answer is:

Density = 930 g/L

To identify the liquid, we need to compare its density with the densities of the known liquids provided.

Tetrahydrofuran: 0.89 g/cm^3 (890 g/L)
Glycerol: 1.3 g/cm^3 (1300 g/L)
Dimethyl sulfoxide: 1.1 g/cm^3 (1100 g/L)
Acetone: 0.79 g/cm^3 (790 g/L)
Ethanolamine: 1.0 g/cm^3 (1000 g/L)

Comparing the density of the unknown liquid (930 g/L) with the known densities, we can see that it falls in between the densities of Glycerol and Dimethyl sulfoxide.

Therefore, based on the density, it is possible that the unknown liquid is either Glycerol or Dimethyl sulfoxide.